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Re: Is there a way to customise math.sqrt(x) for some x?

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On Sat, Jul 16, 2011 at 6:35 PM, Steven D'Aprano
<steve+comp.lang.python@pearwood.info> wrote:
> I have a custom object that customises the usual maths functions and
> operators, such as addition, multiplication, math.ceil etc.
>
> Is there a way to also customise math.sqrt? I don't think there is, but I
> may have missed something.

Only thing I can think of is:

import math
math.sqrt=lambda(x) x.__sqrt__(x) if x.whatever else math.sqrt(x)

I don't suppose there's a lambda version of try/catch?

ChrisA

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Thread

Is there a way to customise math.sqrt(x) for some x? Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-07-16 18:35 +1000
  Re: Is there a way to customise math.sqrt(x) for some x? Chris Angelico <rosuav@gmail.com> - 2011-07-16 19:14 +1000
    Re: Is there a way to customise math.sqrt(x) for some x? Nobody <nobody@nowhere.com> - 2011-07-16 14:42 +0100
    Re: Is there a way to customise math.sqrt(x) for some x? John Nagle <nagle@animats.com> - 2011-07-23 08:31 -0700
  Re: Is there a way to customise math.sqrt(x) for some x? Peter Otten <__peter__@web.de> - 2011-07-16 11:37 +0200
  Re: Is there a way to customise math.sqrt(x) for some x? Gary Herron <gherron@islandtraining.com> - 2011-07-16 08:56 -0700
  Re: Is there a way to customise math.sqrt(x) for some x? rantingrick <rantingrick@gmail.com> - 2011-07-23 14:09 -0700

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