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Groups > comp.lang.python > #72110
| References | <9c8e58be-9619-44c7-8098-961a0134c422@googlegroups.com> |
|---|---|
| Date | 2014-05-27 13:09 +0200 |
| Subject | Re: Regular Expression for the special character "|" pipe |
| From | Vlastimil Brom <vlastimil.brom@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.10368.1401188967.18130.python-list@python.org> (permalink) |
2014-05-27 12:59 GMT+02:00 Aman Kashyap <amankashyap1223@gmail.com>: > I would like to create a regular expression in which i can match the "|" special character too. > > e.g. > > start=|ID=ter54rt543d|SID=ter54rt543d|end=| > > I want to only |ID=ter54rt543d| from the above string but i am unable to write the pattern match containing "|" pipe too. > > By default python treat "|" as an OR operator. > > But in my case I want to use to as a part of search string. > -- Hi, you can just escpape the pipe with backlash like any other metacharacter: r"start=\|ID=ter54rt543d" be sure to use the raw string notation r"...", or you can double all backslashes in the string. hth, vbr
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Regular Expression for the special character "|" pipe Aman Kashyap <amankashyap1223@gmail.com> - 2014-05-27 03:59 -0700
Re: Regular Expression for the special character "|" pipe Vlastimil Brom <vlastimil.brom@gmail.com> - 2014-05-27 13:09 +0200
Re: Regular Expression for the special character "|" pipe Aman Kashyap <amankashyap1223@gmail.com> - 2014-05-27 04:20 -0700
Re: Regular Expression for the special character "|" pipe Daniel <5960761@gmail.com> - 2014-05-27 14:29 +0300
Re: Regular Expression for the special character "|" pipe Aman Kashyap <amankashyap1223@gmail.com> - 2014-05-27 04:39 -0700
Re: Regular Expression for the special character "|" pipe Wolfgang Maier <wolfgang.maier@biologie.uni-freiburg.de> - 2014-05-27 13:55 +0200
Re: Regular Expression for the special character "|" pipe Roy Smith <roy@panix.com> - 2014-05-27 08:35 -0400
Re: Regular Expression for the special character "|" pipe Mark Lawrence <breamoreboy@yahoo.co.uk> - 2014-05-27 14:06 +0100
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