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Groups > comp.soft-sys.math.maple > #337
| From | Axel Vogt <&noreply@axelvogt.de> |
|---|---|
| Newsgroups | comp.soft-sys.math.maple |
| Subject | Re: Series Summation Question |
| Date | 2012-01-28 20:21 +0100 |
| Message-ID | <9oj066Fr04U1@mid.individual.net> (permalink) |
| References | <1fe7f908-df47-4b54-949f-630a50b0551e@j14g2000vba.googlegroups.com> <87vcnywi1u.fsf@san.rr.com> <39d1ff7b-301a-48ee-99a6-3e4d0df84b7a@o13g2000vbf.googlegroups.com> <jftgbn$bt$1@online.de> <jfthpq$18d$1@online.de> |
On 27.01.2012 07:55, Peter Pein wrote:
...
>> Well, if you are interested in the approximation of the sum's value for
>> q=1/10, you should have used NSum in Mathematica:
>>
>> NSum[q^(-6 + 4*n)/(1 - q^(-5 + 4*n)) /. q->1/10, {n, 0, Infinity},
>> WorkingPrecision->20]
>>
>> -21.101200102001001100
>>
>> or - using your workaround - get
>>
>> 6/(5*(-1 + q)) + (1 + 2*q + 3*q^2 + 4*q^3)/(5*(1 + q + q^2 + q^3 + q^4))
>> + (-2*Log[q^4] + Log[1 - q^4] + QPolyGamma[0, 2 - Log[q^5]/Log[q^4],
>> q^4])/(q*Log[q^4])
>>
>> as (hopefully) exact value.
>>
>> Cheers, Peter
>
> Sorry for posting too fast. One gets the result in a more simple form by doing sth. more complicated:
>
> In[1]:= f[q_] = q^(-6 + 4*n)/(1 - q^(-5 + 4*n));
> assum = SumConvergence[f[q], n]
> s[q_] = Together[Subtract @@ (Limit[Sum[f[q], n], n -> #1, Assumptions -> assum] & ) /@ {Infinity, 0}]
> N[s[1/10]]
>
>
> Out[2]= q != 0 && Abs[q]^4 < 1
> Out[3]= (Log[1 - q^4] + QPolyGamma[0, -(Log[q^5]/Log[q^4]), q^4])/(q*Log[q^4])
> Out[4]= -21.1012
I am not aware that Maple has a command to find a
condition for convergence.
And it does not provide a symbolic solution (where
I guess the above cryptic command does just that)
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Series Summation Question clashton <clashton@gmail.com> - 2012-01-25 22:46 -0800
Re: Series Summation Question Axel Vogt <&noreply@axelvogt.de> - 2012-01-26 19:41 +0100
Re: Series Summation Question Joe Riel <joer@san.rr.com> - 2012-01-26 08:21 -0800
Re: Series Summation Question clashton <clashton@gmail.com> - 2012-01-26 16:45 -0800
Re: Series Summation Question Peter Pein <petsie@dordos.net> - 2012-01-27 07:31 +0100
Re: Series Summation Question Peter Pein <petsie@dordos.net> - 2012-01-27 07:55 +0100
Re: Series Summation Question clashton <clashton@gmail.com> - 2012-01-28 07:59 -0800
Re: Series Summation Question Axel Vogt <&noreply@axelvogt.de> - 2012-01-28 20:21 +0100
Re: Series Summation Question Peter Pein <petsie@dordos.net> - 2012-02-02 12:21 +0100
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