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Groups > comp.lang.python > #12596
| From | Bart Kastermans <bkasterm@gmail.com> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | List comprehension timing difference. |
| Date | 2011-09-01 18:35 -0600 |
| Organization | MB-NET.NET for Open-News-Network e.V. |
| Message-ID | <87zkinkcht.fsf@gmail.com> (permalink) |
In the following code I create the graph with vertices
sgb-words.txt (the file of 5 letter words from the
stanford graphbase), and an edge if two words differ
by one letter. The two methods I wrote seem to me to
likely perform the same computations, the list comprehension
is faster though (281 seconds VS 305 seconds on my dell mini).
Is the right interpretation of this timing difference
that the comprehension is performed in the lower level
C code?
As this time I have no other conjecture about the cause.
---------------------------------------------------------
import time
import copy
data = map (lambda x: x.strip(), open('sgb-words.txt').readlines())
def d (w1, w2):
count = 0
for idx in range(0,5):
if w1[idx] != w2[idx]:
count += 1
return count
print "creating graph"
t0 = time.clock ()
graph = [[a,b] for a in data for b in data if d(a,b) ==1 and a < b]
t1 = time.clock ()
print "took " + str (t1 - t0) + " seconds."
t0 = time.clock ()
graph2 = []
for i in range (0, len(data)):
for j in range(0,len(data)):
if d(data[i],data[j]) == 1 and i < j:
graph2.append ([i,j])
t1 = time.clock ()
print "took " + str (t1 - t0) + " seconds."
Back to comp.lang.python | Previous | Next — Next in thread | Find similar | Unroll thread
List comprehension timing difference. Bart Kastermans <bkasterm@gmail.com> - 2011-09-01 18:35 -0600
Re: List comprehension timing difference. MRAB <python@mrabarnett.plus.com> - 2011-09-02 02:12 +0100
Re: List comprehension timing difference. Bart Kastermans <bkasterm@gmail.com> - 2011-09-02 07:54 -0600
Re: List comprehension timing difference. ting@thsu.org - 2011-09-02 07:50 -0700
Re: List comprehension timing difference. Bart Kastermans <bkasterm@gmail.com> - 2011-09-02 20:15 -0600
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