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Re: Bug? `set -e` inside functions inside `$(...)`

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  Re: Bug? `set -e` inside functions inside `$(...)` John W <jwdevel@gmail.com> - 2019-10-03 17:58 -0700

#15471 — Re: Bug? `set -e` inside functions inside `$(...)`

Ah, got it sorted out.

Not a bug, of course (:

Bash, when not in posix mode, clears the '-e' flag in subshell environments.

On 10/3/19, John W <jwdevel@gmail.com> wrote:
> I'm seeing some strange behavior w/regard to `set -e` when invoking a
> shell function through a `$(...)` construct.
>
> I can't tell if it's a bug or not; the manpage doesn't really mention
> $() specially with regard to `set -e`, that I have found.
>
> I made a SO post with a bunch of details here:
> https://stackoverflow.com/questions/58228383/bash-set-e-reset-inside-functions-when-run-via
>
> But here's my small repro program:
>
>     #!/usr/bin/env bash
>
>     echo "Initial:    $-"
>     set -eu
>     echo "After set:  $-"
>
>     function foo() {
>         echo "Inside foo: $-"
>     }
>     foo
>
>     function bar() {
>         false    # I'd expect this to immediately fail
>         echo "Inside bar: $-"
>     }
>     # When a $(...) construct is involved, 'bar' runs to completion!
>     x=$(bar)
>     echo "We should never get here ... but we do."
>     echo "$x"
>
> For me, this ouputs:
>
>     Initial:    hB
>     After set:  ehuB
>     Inside foo: ehuB
>     We should never get here ... but we do.
>     Inside bar: huB
>
> and it's really the last two lines that confuse me. Why was 'set -e'
> disabled inside of "bar"?
>
> Is this documented behavior, and I missed it?
> Or a bug?
> Or makes sense under some interpretation of things that I'm not grasping?
>
> Thanks for any advice
> -John
>

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