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Re: Error on arithmetic evaluation of `~0`.

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  Re: Error on arithmetic evaluation of `~0`. Chet Ramey <chet.ramey@case.edu> - 2018-12-26 12:10 -0500

#14959 — Re: Error on arithmetic evaluation of `~0`.

On 12/23/18 12:01 PM, Bize Ma wrote:
> Chet Ramey (<chet.ramey@case.edu <mailto:chet.ramey@case.edu>>) wrote:
> 
>     >
>     > While this works:
>     >
>     > var=(hello); echo "${var[ ~0]}"
>     > hello
> 
>     Because negative array subscripts count backwards from the end of the
>     array.
> 
> 
> Doh!, yes. And, because of that: "${var[-1]}"
> should give the *last* element of array "var", shouldn't it?

Yes, if it's an array variable.

> Consequently,  this happens:
> 
>     $ unset var; var[0]=77; echo "${var[0]}"; echo "${var[-1]}"
>     77
>     77
>  
> The only value in var is at index 0, which means it is also the *last* value.

Correct.

> 
> The point being that a variable which has an scalar value "var=hello"
> should act (for most practical cases) as an array for which only the
> value at address 0 has been defined.
> 
> Both command line above should have printed "hello".

No. 0 is the only valid subscript for a non-array variable. The difference
between bash and other shells that implement this feature is that bash
warns about negative subscripts.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
		 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/

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