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BASH_ARG{C,V} set when sourcing, even without extdebug

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  BASH_ARG{C,V} set when sourcing, even without extdebug Grisha Levit <grishalevit@gmail.com> - 2015-11-09 22:59 -0800
    Re: BASH_ARG{C,V} set when sourcing, even without extdebug Chet Ramey <chet.ramey@case.edu> - 2015-11-10 09:31 -0500

#11855 — BASH_ARG{C,V} set when sourcing, even without extdebug

It looks like the source builtin pushes its own argc and argv onto the arrays but only if it is called with no other arguments.

$ cat /tmp/s
fun() { declare -p BASH_ARGC BASH_ARGV; }
fun arg

$ shopt -u extdebug; source /tmp/s
declare -a BASH_ARGC=([0]="1")
declare -a BASH_ARGV=([0]="/tmp/s")

$ shopt- u extdebug; source /tmp/s foo
declare -a BASH_ARGC=()
declare -a BASH_ARGV=()

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#11858

On 11/10/15 1:59 AM, Grisha Levit wrote:
> It looks like the source builtin pushes its own argc and argv onto the arrays but only if it is called with no other arguments.

Yes, bash has always done this as a convenience.  This is a way to get the
name of the sourced file in the common case.

When given additional arguments, bash sets BASH_ARGC and BASH_ARGV only
when debugging mode is in effect.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
		 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/

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