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Groups > gnu.bash.bug > #13779
| From | Robert Elz <kre@munnari.OZ.AU> |
|---|---|
| Newsgroups | gnu.bash.bug |
| Subject | Re: Unset array doesn't work |
| Date | 2018-03-01 05:38 +0700 |
| Message-ID | <mailman.9914.1519857591.27995.bug-bash@gnu.org> (permalink) |
| References | (6 earlier) <755d61fa-d2bc-8855-bc30-4388aff40691@gmail.com> <9974.1519637469@jinx.noi.kre.to> <15717.1519764581@jinx.noi.kre.to> <24248.1519844400@jinx.noi.kre.to> <20180228200051.ilzre3k4y7intd76@eeg.ccf.org> |
Date: Wed, 28 Feb 2018 15:14:58 -0500
From: Chet Ramey <chet.ramey@case.edu>
Message-ID: <b4615d2e-cf2f-ea60-c8c6-44b6eb8dba76@case.edu>
| Yes, that's what I said. In the current scope, unset arranges for the
| variable to appear unset. In a previous scope, unset just removes the
| variable, which uncovers an instance of the variable at a (further)
| previous scope.
Were I you, I would simply change the "in a previous scope" behaviour to
match the "in the current scope" behaviour. That makes it consistent,
and rational.
I cannot believe that there is anything anywhere which depends upon the
current weirdness.
I'd also forget "remove" as anything that unset is supposed to achieve,
and I would change "appear" to "be" in the description of the current scope
behaviour.
kre
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Re: Unset array doesn't work Robert Elz <kre@munnari.OZ.AU> - 2018-03-01 05:38 +0700
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