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| From | Chet Ramey <chet.ramey@case.edu> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: Unset array doesn't work |
| Date | Wed, 28 Feb 2018 15:14:58 -0500 |
| Lines | 22 |
| Approved | bug-bash@gnu.org |
| Message-ID | <mailman.9903.1519848908.27995.bug-bash@gnu.org> (permalink) |
| References | <ba594d01-b9c4-5cd8-9fa0-2f20fd1d2d07@case.edu> <21679c48-4064-5683-2d5f-91bfb76687d0@case.edu> <790ade74-690f-541c-9ab4-6359917442d0@case.edu> <a56e05b1-0b34-1cb2-6073-91c12f27e228@gmail.com> <a642644f-e475-6361-140e-5b47ab4e321c@case.edu> <755d61fa-d2bc-8855-bc30-4388aff40691@gmail.com> <9974.1519637469@jinx.noi.kre.to> <15717.1519764581@jinx.noi.kre.to> <24248.1519844400@jinx.noi.kre.to> <20180228200051.ilzre3k4y7intd76@eeg.ccf.org> |
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On 2/28/18 3:00 PM, Greg Wooledge wrote: > Does unset create some kind of "placeholder" in the current function > (but not in a caller)? Yes, that's what I said. In the current scope, unset arranges for the variable to appear unset. In a previous scope, unset just removes the variable, which uncovers an instance of the variable at a (further) previous scope. It looks like I added that code in 1995. The code before that was "pure" dynamic scoping, in the sense that it just removed the variable and `uncovered' a previous scope's value no matter where the variable was declared. It seems like I added the special case for several reasons, but there's no indication of widespread user complaint about the behavior of `unset'. (Of course, that was a long time ago.) -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, UTech, CWRU chet@case.edu http://tiswww.cwru.edu/~chet/
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Re: Unset array doesn't work Chet Ramey <chet.ramey@case.edu> - 2018-02-28 15:14 -0500
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