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| From | Greg Wooledge <wooledg@eeg.ccf.org> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: bash 4.4.19 |
| Date | Wed, 19 Sep 2018 08:50:23 -0400 |
| Lines | 14 |
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On Wed, Sep 19, 2018 at 08:38:59AM +0300, Евгений Мёдов wrote:
> for i in {1..5}; do
> A A var${i}=$RANDOM
> done
What you want is an array. See <https://mywiki.wooledge.org/BashFAQ/005>.
for i in 1 2 3 4 5; do
var[i]=$RANDOM
done
echo "${var[1]}"
declare -p var
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Re: bash 4.4.19 Greg Wooledge <wooledg@eeg.ccf.org> - 2018-09-19 08:50 -0400
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