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| From | worley@alum.mit.edu (Dale R. Worley) |
| Newsgroups | gnu.bash.bug |
| Subject | Re: EOF not disabled in readline |
| Date | Sun, 26 Jul 2020 02:27:29 -0400 |
| Lines | 39 |
| Approved | bug-bash@gnu.org |
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| To | Grisha Levit <grishalevit@gmail.com> |
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Grisha Levit <grishalevit@gmail.com> writes:
> It seems that disabling the EOF character does not have an effect on
> readline. For example:
>
> $ stty sane
> $ stty eof undef
> $ ^D
> Use "logout" to leave the shell.
> $ read -e; echo $?
> ^D
> 1
That's messy!
When you execute "read -e", you get "If the standard input is coming
from a terminal, readline (see READLINE above) is used to obtain the
line."
In readline, "Line editing is also used when using the -e option to the
read builtin. By default, the line editing commands are similar to those
of Emacs."
But of course, in Emacs, C-d is "delete forward character", and that is
duplicated in readline:
delete-char (C-d)
Delete the character at point. If point is at the beginning of
the line, there are no characters in the line, and the last
character typed was not bound to delete-char, then return EOF.
So when you type C-d, it goes into bash as a character, readline reads
it, and returns EOF to its caller, "read". And for "read", "The return
code is zero, unless end-of-file is encountered ...".
You can verify that analysis by running your example, but instead of
typing a single C-d, type X C-b C-d, and see that that C-d deletes the
X, rather than causing readline to return EOF.
Dale
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Re: EOF not disabled in readline worley@alum.mit.edu (Dale R. Worley) - 2020-07-26 02:27 -0400
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