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| From | Linda Walsh <bash@tlinx.org> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: BUG?: (or what's going on?) test for NL == NL fails (bash-4.3.39(3)-release) |
| Date | Sun, 02 Aug 2015 15:11:17 -0700 |
| Lines | 22 |
| Approved | bug-bash@gnu.org |
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| To | Charles Daffern <seejay.11@gmail.com>, bug-bash <bug-bash@gnu.org> |
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Charles Daffern wrote:
> On 02/08/15 20:30, Linda Walsh wrote:
>>> if [[ $(printf "\n") == $'\n' ]]; then echo T; else echo F; fi
>> F
>
> The command substitution operators ($(...) and `...`) strip all trailing
> linefeeds. You are left with an empty string here.
>
> The usual workarounds I see (where necessary) are hacks like this:
>
> variable=$(command; echo x); variable=${variable%?x}
----
I see what you mean --- erk...
I think the process substitution doesn't, since you need
to explicitly use a -t switch if you want to strip the "\n"'s off
Thanks!
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Re: BUG?: (or what's going on?) test for NL == NL fails (bash-4.3.39(3)-release) Linda Walsh <bash@tlinx.org> - 2015-08-02 15:11 -0700
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