Re: Shell exits after process substitution when using DEBUG trap with extdebug

From	Jonathan Rascher <jon@bcat.name>
Newsgroups	gnu.bash.bug
Subject	Re: Shell exits after process substitution when using DEBUG trap with extdebug
Date	2020-08-04 09:29 -0500
Message-ID	<mailman.757.1596551388.2739.bug-bash@gnu.org> (permalink)
References	<CAFG5iOhJ61520b7DKiHbjSAOcR01jHOhnYa-biv9dTowK11Vtg@mail.gmail.com> <fe173c2c-1743-cf9e-4a28-64337dbc9062@case.edu> <CAFG5iOijac5OgdvvzC8d1wAMLJ=K-N3kzP=dahgV5=skd8+2=g@mail.gmail.com>

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On Tue, Aug 4, 2020 at 9:20 AM Chet Ramey <chet.ramey@case.edu> wrote:

> On 8/3/20 9:44 PM, Jonathan Rascher wrote:
> > $ bash --version
> > GNU bash, version 5.0.3(1)-release (x86_64-pc-linux-gnu)
> >
> > $ uname -a
> > Linux penguin 5.4.40-04224-g891a6cce2d44 #1 SMP PREEMPT Tue Jun 23
> 20:21:29
> > PDT 2020 x86_64 GNU/Linux
> >
> > (This is a Pixelbook running the default Crostini Linux VM under Chrome
> > OS 84.0.4147.110. I can reproduce the issue on regular Debian too,
> though.)
> >
> > To reproduce, run the following commands:
> >
> > shopt -s extdebug
> > trap : DEBUG
> > : < <(:)
>
> Thanks for the report. I can't reproduce this with macOS, but I can with
> RHEL 7. I'll take a look.
>

Thanks!

The EOF hunch made me decide to see what happened with ignoreeof set. Sure
enough, instead of exiting when I type the first character after the
command with the process substitution, bash just prints `Use "exit" to
leave the shell.` And then the character I actually typed is still echoed
to the console, and I can keep using the shell. (It doesn't exit if
ignoreeof is set.)

Cheers,
Jon

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Re: Shell exits after process substitution when using DEBUG trap with extdebug Jonathan Rascher <jon@bcat.name> - 2020-08-04 09:29 -0500

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