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Re: Assignment of $* to a var removes spaces on unset IFS.

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2018-08-13 22:09 GMT-04:00 Eduardo A. Bustamante López <dualbus@gmail.com>:

> On Mon, Aug 13, 2018 at 09:36:23PM -0400, Bize Ma wrote:
> (...)
> > Please, do not waste our time in incorrect claims.
> >
> > Do your homework and test !
> (...)
>
>



> dualbus@ubuntu:~/src/gnu/bash$ bash /tmp/script
> 4.4.19(1)-release
> [foo bar baz quux][  foo     bar  baz     quux  ]
>
>
So, it is confirmed that the bug exists in the present release, Is it not?

> Did you test Bash 5.0? Because that's where the current bug fixes are
going to.

So, is it a "wont fix" for 4.4 (present release) ?


> I don't see Chet releasing a new version of 4.4 to fix something that's
already
> fixed there.

That version is not even beta, it is still alpha, are you asking that
everyone should use
non-released (and not yet tested as beta) alpha release ?


> dualbus@ubuntu:~/src/gnu/bash$ cat /tmp/script
> echo $BASH_VERSION
> set -- "  foo  "    "  bar  baz  "  "  quux  "
> unset IFS
> a=$*
> b="$*"
> printf '[%s]' "$a" "$b"; echo

Thanks for copying the supplied script.....



> dualbus@ubuntu:~/src/gnu/bash$ ./bash /tmp/script
> 5.0.0(1)-alpha
> [  foo     bar  baz     quux  ][  foo     bar  baz     quux  ]
>
>
Thanks for testing. !!


> Please read this thread:
>
> * http://lists.nongnu.org/archive/html/bug-bash/2017-09/msg00058.html
>

So? It is not solved in that thread, it is even said that:

 > This is a bug in bash and it should be fixed, not excused.

To which I agree. After a year, nothing else have been said about it.

It seems about time to get it solved. Or say that it won't be.

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Re: Assignment of $* to a var removes spaces on unset IFS. Bize Ma <binaryzebra@gmail.com> - 2018-08-13 22:52 -0400

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