Re: Bash removes unrequested characters in bracket expressions (not a range).

From	Chet Ramey <chet.ramey@case.edu>
Newsgroups	gnu.bash.bug
Subject	Re: Bash removes unrequested characters in bracket expressions (not a range).
Date	2018-11-28 08:59 -0800
Message-ID	<mailman.5075.1543846810.1284.bug-bash@gnu.org> (permalink)
References	<CAFra36hcAjBHGgd_8sHjOV4wSzjmdCyLV2aQo8Ww1bwJqkxYQA@mail.gmail.com> <1c24a279-f439-a13c-be60-901096ccd4e1@case.edu> <CAFra36hdkG+5qq94cf-sbKrnw6roJWez03aKJPU=Z=Vad2LaXg@mail.gmail.com> <63b8941d-16bc-0761-7272-83eb7347354e@case.edu> <CAFra36g5PNVzR_=kiJYQDNXm55s0qM=5AKXXoDeb0moTjfaLEg@mail.gmail.com>

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On 11/28/18 2:29 AM, Bize Ma wrote:
> Chet Ramey (<chet.ramey@case.edu <mailto:chet.ramey@case.edu>>) wrote:
> 
>     On 11/24/18 4:32 PM, Bize Ma wrote:
> 
>  [...]
> 
>     > I have been made aware that there is a
>     >       cstart = cend = FOLD (cstart);
>     > inside the `sm_loop.c` file that will convert into a range many
>     > individual character. If that understanding is correct that is the
>     > source of the difference with other shells.
> 
>     I'm not sure what you mean by "convert into a range." If cstart and cend
>     were treated as a range, the start end and end characters would be the
>     same. If cstart == cend, a character that collates >= cstart and <= cend
>     would have to collate equal to cstart and cend.
> 
> 
> Yes, exactly, a range where the start and the end are the same.

A range like that is exactly equivalent to a single ordinary character.

POSIX: "An ordinary character in the list should only match that character,
but may match any single character that collates equally with that
character"

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
		 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/

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Re: Bash removes unrequested characters in bracket expressions (not a range). Chet Ramey <chet.ramey@case.edu> - 2018-11-28 08:59 -0800

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