Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > gnu.bash.bug > #14409
| From | Frank <sales@eec.com> |
|---|---|
| Newsgroups | gnu.bash.bug |
| Subject | Re: declare(1) not executing inside source'd script |
| Date | 2018-07-27 10:44 -0400 |
| Message-ID | <mailman.4332.1532702729.1292.bug-bash@gnu.org> (permalink) |
| References | <20180727042606.EFCD8120EA6@student.eeconsulting.net> <20180727140939.eah2hckwkvspngwc@eeg.ccf.org> |
Agreed. But the bash installation does create a man page for it, does it not? So a command like, “man 1 declare” does work...? I always thought this was somewhat incongruous. -- Frank Edwards Edwards & Edwards Consulting, LLC Hours: 10A-6P ET Phone: (813) 406-0604 Sent from my iPhone. No electrons were harmed in the creation or transmission of this message. > On Jul 27, 2018, at 10:09 AM, Greg Wooledge <wooledg@eeg.ccf.org> wrote: > >> On Fri, Jul 27, 2018 at 12:26:06AM -0400, frank@eec.com wrote: >> produce any output (making me think that declare(1) >> isn't being executed at all). > > For the record, declare is a builtin, not an external command with a > man page in the (1) section, so writing "declare(1)" is extremely > misleading.
Back to gnu.bash.bug | Previous | Next | Find similar | Unroll thread
Re: declare(1) not executing inside source'd script Frank <sales@eec.com> - 2018-07-27 10:44 -0400
csiph-web