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Groups > gnu.bash.bug > #14811
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| From | Greg Wooledge <wooledg@eeg.ccf.org> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: Strange behaviour from jobs -p in a subshell |
| Date | Tue, 13 Nov 2018 10:09:41 -0500 |
| Lines | 19 |
| Approved | bug-bash@gnu.org |
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On Tue, Nov 13, 2018 at 09:59:51AM -0500, Chet Ramey wrote: > On 11/13/18 4:28 AM, Christopher Jefferson wrote: > > Consider the following script. While the 3 sleeps are running, both jobs > > -p and $(jobs -p) will print 3 PIDs. Once the 3 children are finished, > > jobs -p will continue to print the 3 PIDs of the done Children, but > > $(jobs -p) will only print 1 PID. $(jobs -p) always seems to print at > > most 1 PID of a done child. > > Since the $(jobs -p) is run in a subshell, its knowledge of its parent's > jobs is transient. In this case, the subshell deletes knowledge of the > jobs it inherits from its parent, but hangs onto the last asynchronous job > in case the subshell references $!. > > Chet If the goal is to obtain the result of "jobs -p" and use it in a script, I would suggest redirecting the output of jobs -p to a temp file, then reading it. That skips the subshell.
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Re: Strange behaviour from jobs -p in a subshell Greg Wooledge <wooledg@eeg.ccf.org> - 2018-11-13 10:09 -0500
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