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Re: delcare -a on a nameref in a function modifies nameref instead of target

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From Grisha Levit <grishalevit@gmail.com>
Newsgroups gnu.bash.bug
Subject Re: delcare -a on a nameref in a function modifies nameref instead of target
Date Thu, 19 Jul 2018 13:20:12 -0400
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On Wed, Jul 18, 2018 at 8:23 AM Greg Wooledge <wooledg@eeg.ccf.org> wrote:
> FYI that one is already fixed in 5.0-alpha:
>
> wooledg:~$ declare -n ref=var; declare -a ref=(X); declare -p ref var
> declare -n ref="var"
> declare -a var=([0]="X")
> wooledg:~$ f() { declare -n ref=var; declare ref=(X); declare -p ref var; }; f
> declare -an ref=([0]="X")
> declare -a var=([0]="X")
>
> Or at least partly fixed. *shrug*

I think you are just seeing `var' have a value after the function call
because it's still there from the global `declare' invocations.

With bash 5.0 alpha, running just the version that's wrapped in a
function, I don't get any value for `var':

    $ echo $BASH_VERSION
    5.0.0(1)-alpha
    $ f() { declare -n ref=var; declare ref=(X); declare -p ref var; }; f
    declare -an ref=([0]="X")
    bash: declare: var: not found

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Re: delcare -a on a nameref in a function modifies nameref instead of target Grisha Levit <grishalevit@gmail.com> - 2018-07-19 13:20 -0400

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