Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > gnu.bash.bug > #14320

Re: Number with sign is read as octal despite a leading 10#

Show key headers only | View raw

On Tue, Jul 10, 2018 at 1:44 PM, Ilkka Virta <itvirta@iki.fi> wrote:

> I think the problematic case here is when the number comes as input from
> some program, which might or might not print a leading sign or leading
> zeroes, but when we know that the number is, in any case, decimal.
>
> E.g. 'date' prints leading zeroes, which is easy enough to handle:
>
> hour=$(date +%H)
>
> hour=${hour#0}         # remove one leading zero, or
> hour="10#$hour"        # make it base-10
>
> The latter works even with more than one leading zero, but neither works
> with a sign. So, handling numbers like '-00159' gets a bit annoying:
>
> $ num='-00159'
> $ num="${num:0:1}10#${num:1}"; echo $(( num + 1 ))
> -158
>
> And that's without checking that the sign was there in the first place.
>
>
> Something like that will probably not be too common, but an easier way to
> force any number to be interpreted in base-10 (regardless of leading
> zeroes) could be useful. If there is a way, I'd be happy to hear.



It's not too complicated to separate the sign from the number eg:

for num in 159 000159 +000159 -000159;do
   echo $((${num%%[!+-]*}10#${num#[-+]}))
done

Back to gnu.bash.bug | Previous | Next | Find similar | Unroll thread

Thread

Re: Number with sign is read as octal despite a leading 10# Pierre Gaston <pierre.gaston@gmail.com> - 2018-07-10 19:16 +0300

csiph-web