Re: 'foo > >(bar)' doesn't set $! for external foo not invoked via 'command'

From	Chet Ramey <chet.ramey@case.edu>
Newsgroups	gnu.bash.bug
Subject	Re: 'foo > >(bar)' doesn't set $! for external foo not invoked via 'command'
Date	2020-07-20 08:57 -0400
Organization	ITS, Case Western Reserve University
Message-ID	<mailman.224.1595249883.24492.bug-bash@gnu.org> (permalink)
References	<20200719204836.GA1184@mutt> <CAH7i3Lqre0SoX_nJaMis=g7T_+X1LtrsPWJiJCjRCrHT1Y4_Jw@mail.gmail.com> <1659625e-267d-402e-c199-0772820fed79@case.edu>

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On 7/20/20 1:10 AM, Oğuz wrote:

>> Bash Version: 5.0
>> Patch Level: 17
>> Release Status: release
>>
>> Description:
>>         $! isn't set to the PID of 'bar' for
>>
>>                 foo > >(bar)
>>
>>         if 'foo' is an external program (as opposed to a builtin or
>>         function) - unless it's invoked via 'command'.

Redirections are performed in the subshell created to execute `foo', so the
process substitution is invoked there and can't affect the parent's $!.


-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
		 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/

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Re: 'foo > >(bar)' doesn't set $! for external foo not invoked via 'command' Chet Ramey <chet.ramey@case.edu> - 2020-07-20 08:57 -0400

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