Re: hash -l with empty hash table prints to stdout

From	Lawrence Velázquez <vq@larryv.me>
Newsgroups	gnu.bash.bug
Subject	Re: hash -l with empty hash table prints to stdout
Date	2020-06-17 00:27 -0400
Message-ID	<mailman.2037.1592368082.2541.bug-bash@gnu.org> (permalink)
References	(2 earlier) <447bbb87-ce9a-e038-5a00-68646f9771c4@archlinux.org> <067bf5a9-72ba-f6f6-a170-d1ebaa54919b@case.edu> <69a0b336-4f2e-3c9f-cacf-79358ed33bf4@archlinux.org> <083a2961-fd80-fbc8-4cf6-7ea30cf0c8e7@case.edu> <6BEEDF71-B645-4ED3-96DF-D97B9BDE3759@larryv.me>

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> On Jun 16, 2020, at 10:51 AM, Chet Ramey <chet.ramey@case.edu>
> wrote:
> 
>> On 6/16/20 10:26 AM, Eli Schwartz wrote:
>> 
>>> On 6/16/20 9:56 AM, Chet Ramey wrote:
>>> 
>>> It's not a warning; there's nothing to warn about. An empty hash
>>> table is not an exceptional condition. It's simply informational.
>> 
>> Then would you say it is debug info?
> 
> No, not at all. What are you trying to debug?
> 
> Maybe it would be better to remove the message entirely and only
> display it in compatibility mode.

The user-friendly way to view the table is by running `hash` without
arguments. It prints "hash table empty" as well, which makes sense in
that context. Given that, it makes sense to me to change `hash -l`,
which is expressly intended for scripting use, to output nothing when
the table is empty.

vq

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Re: hash -l with empty hash table prints to stdout Lawrence Velázquez <vq@larryv.me> - 2020-06-17 00:27 -0400

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