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Re: Combination of "eval set -- ..." and $() command substitution is slow

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On 15.7. 20:49, Robert Elz wrote:

> 			printf '%s\n' "`printf %s "$i"`"
> 			printf '%s\n' "$(printf %s "$i")"
> 
> aren't actually the same.   In the first $i is unquoted, in the second it is
> quoted.   

Huh, really? It looks to me like the first one treats $i as quoted too:

  $ touch file.txt; i='123 *'
  $ printf '%s\n' "`printf :%s: "$i"`"
  :123 *:

But not here, of course:

  $ printf '%s\n' "`printf :%s: $i`"
  :123::file.txt:

I tried with Bash and some other shells, but couldn't find one where the 
result was different. Did I miss something?


-- 
Ilkka Virta / itvirta@iki.fi

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Re: Combination of "eval set -- ..." and $() command substitution is slow Ilkka Virta <itvirta@iki.fi> - 2019-07-16 12:18 +0300

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