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Groups > gnu.bash.bug > #16820
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|---|---|
| From | Robert Elz <kre@munnari.OZ.AU> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: How do we intercept file saving or output to stdout directly |
| Date | Thu, 27 Aug 2020 05:26:46 +0700 |
| Lines | 30 |
| Approved | bug-bash@gnu.org |
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| To | Greg Wooledge <wooledg@eeg.ccf.org> |
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Date: Wed, 26 Aug 2020 08:13:52 -0400
From: Greg Wooledge <wooledg@eeg.ccf.org>
Message-ID: <20200826121352.GN931@eeg.ccf.org>
| The obvious guess is that it's to "prevent you from accidentally
| overwriting a file".
That would be what one would normally assume, but Dale didn't
show what comes just before the open (this sys call trace is
from a different OS, so the format is different)
28469 28469 xkbcomp CALL unlink(0x7f7fffffec7b)
28469 28469 xkbcomp NAMI "/dev/stdout"
28469 28469 xkbcomp RET unlink -1 errno 13 Permission denied
28469 28469 xkbcomp CALL open(0x7f7fffffec7b,0xa01,0x1b6)
28469 28469 xkbcomp NAMI "/dev/stdout"
28469 28469 xkbcomp RET open -1 errno 17 File exists
If it was attempting to "prevent you from accidentally overwriting a file"
it is unlikely it would be unlinking it (or attempting to) first.
(0xa01 == O_EXCL|O_CREAT|O_WRONLY 0x1b6 == 0666).
If one were to execute xkbcomp as root (people, please don't)
then all of this would probably succeed, and replace /dev/stdout
with a regular file containing the xkbcomp output.
kre
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Re: How do we intercept file saving or output to stdout directly Robert Elz <kre@munnari.OZ.AU> - 2020-08-27 05:26 +0700
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