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Re: ${1+"$@"} does not generate multiple words if IFS is empty

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martijn@inlv.org writes:

> 	The substitution ${1+"$@"} should resolve to "$@" if there is at
> 	least one parameter -- i.e. one word per parameter. This works fine
> 	if IFS contains any character or is unset. If IFS is empty, it
> 	instead resolves to the equivalent of "$*", i.e. a single word
> 	concatenating all the parameters without a separator. IFS should
> 	not influence the behaviour of "$@" under any circumstances.

http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_06_05

"If the value of IFS is null, no field splitting shall be performed."

Andreas.

-- 
Andreas Schwab, schwab@linux-m68k.org
GPG Key fingerprint = 58CA 54C7 6D53 942B 1756  01D3 44D5 214B 8276 4ED5
"And now for something completely different."

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Re: ${1+"$@"} does not generate multiple words if IFS is empty Andreas Schwab <schwab@linux-m68k.org> - 2015-12-30 10:02 +0100

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