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Re: test -v for array does not work as documented

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On 2/20/20 10:05 AM, Ulrich Mueller wrote:
>>>>>> On Thu, 20 Feb 2020, pepa65 wrote:
> 
>> On 20/02/2020 19.48, Ulrich Mueller wrote:
>>> Still, I think it's sad that there isn't a command that can test for
>>> assigned vs void variable, without the need for parsing of declare -p
>>> output.
> 
>> There is no need to parse, the return value of `declare -p var` or
>> `typeset -p var` will tell you what you want.
> 
> Unfortunately, it doesn't:
> 
>    $ f() {
>    >   local var
>    >   var="foo"
>    >   declare -p var
>    >   echo $?
>    >   unset var
>    >   declare -p var
>    >   echo $?
>    > }
>    $ f
>    declare -- var="foo"
>    0
>    declare -- var
>    0

It's unset because it doesn't have a value, but it retains the `local'
attribute so it stays local if subsequently assigned one.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
		 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/

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Re: test -v for array does not work as documented Chet Ramey <chet.ramey@case.edu> - 2020-02-20 14:37 -0500

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