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Groups > gnu.bash.bug > #16543

Re: Return from function depending on number of parameters

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On Fri, Jul 03, 2020 at 07:00:54PM +0100, Chris Elvidge wrote:
> I've used 'return $((!$#))' and 'return $[!$#]' to return an error if no
> parameters given to function.

The problem with this is that it *always* returns from the function,
even when paramters are given.

If you actually want to do what you said, you need a conditional check
of some kind, either "if" or "||".

(($#)) || return 1

would be my preference, if you really do not want to give any kind of
error message to indicate *why* you are returning with a failure code.

If you want to add an error message, then I would go with "if".

if ((! $#)); then
  echo "usage: myfunc arg1 ..." >&2
  return 1
fi

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Re: Return from function depending on number of parameters Greg Wooledge <wooledg@eeg.ccf.org> - 2020-07-06 07:50 -0400

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