[Python-de] Re: regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing"

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From	Christopher Arndt <chris@chrisarndt.de>
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Subject	[Python-de] Re: regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing"
Date	Thu, 8 Dec 2022 09:04:03 +0100
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Am 08.12.22 um 08:20 schrieb robert rottermann:
 > Muss ich noch irgend ein Flag setzen?
a) Du solltest Raw Strings verwenden:

regex = r"..."

b) Statt "\r\n" zu matchen, verwende re.MULTILINE und "^" und "$".

c) Regular expressions sind für so was nur bedingt geeignet, besser wäre 
es einen Parser zu definieren, z.B. mit PyParsing:

https://github.com/pyparsing/pyparsing/blob/master/examples/configParse.py

Chris

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[Python-de] regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing" robert rottermann <robert@redcor.ch> - 2022-12-08 08:20 +0100
  [Python-de] Re: regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing" Christopher Arndt <chris@chrisarndt.de> - 2022-12-08 09:04 +0100
    [Python-de] Re: regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing" Matthias Urlichs <matthias@urlichs.de> - 2022-12-09 17:41 +0100
  Re: [Python-de] regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing" "Peter J. Holzer" <hjp-usenet3@hjp.at> - 2022-12-08 12:29 +0100
  [Python-de] Re: regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing" Stefan Schwarzer <sschwarzer@sschwarzer.net> - 2022-12-08 15:07 +0100
    Re: [Python-de] Re: regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing" "Peter J. Holzer" <hjp-usenet3@hjp.at> - 2022-12-08 22:46 +0100
  [Python-de] Re: regex: Ausdruck matches wen auf einer Zeile, fails when "freespacing" Stefan Schwarzer <sschwarzer@sschwarzer.net> - 2022-12-08 15:14 +0100

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