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Groups > comp.unix.shell > #4212
| From | Paul Branon <paulbranon@googlemail.com> |
|---|---|
| Newsgroups | comp.unix.shell |
| Subject | Re: how to get arguments in a function split according to certain delimiters? |
| Date | 2012-02-27 05:26 -0800 |
| Organization | http://groups.google.com |
| Message-ID | <d02a2e00-faaf-4fe4-b77a-7258e0e00a3d@eb6g2000vbb.googlegroups.com> (permalink) |
| References | <97de1354-edd8-4eec-a660-8e921f55b326@s7g2000vby.googlegroups.com> <barmar-922110.01422927022012@news.eternal-september.org> <5647a316-33b3-436a-94c6-6e948eb554ab@d17g2000vba.googlegroups.com> |
On Feb 27, 11:20 am, Paul Branon <paulbra...@googlemail.com> wrote: > On Feb 27, 6:42 am, Barry Margolin <bar...@alum.mit.edu> wrote: > > > > > > > > > > > In article > > <97de1354-edd8-4eec-a660-8e921f55b...@s7g2000vby.googlegroups.com>, > > > Selva <kobu.se...@gmail.com> wrote: > > > bash-3.2$ set | grep IFS > > > IFS=: > > > bash-3.2$ echo jungles:of:brazil > > > jungles:of:brazil > > > > I want echo to get the arguments: 1=jungles, 2=of, 3=brazil > > > foo=jungles:of:brazil > > echo $foo > > > -- > > Barry Margolin, bar...@alum.mit.edu > > Arlington, MA > > *** PLEASE post questions in newsgroups, not directly to me *** > > Barry, what does that do? Doesn't it just echo "jungles:of:brazil" > which is not what the op wants I added quotes to Barry's suggestion and tripped myself up. quotes, quotes, quotes!!! IFS=:; foo="jungles:of:brazil"; echo $foo and IFS=:; foo="jungles:of:brazil"; echo "$foo"
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how to get arguments in a function split according to certain delimiters? Selva <kobu.selva@gmail.com> - 2012-02-26 21:49 -0800
Re: how to get arguments in a function split according to certain delimiters? Barry Margolin <barmar@alum.mit.edu> - 2012-02-27 01:42 -0500
Re: how to get arguments in a function split according to certain delimiters? Paul Branon <paulbranon@googlemail.com> - 2012-02-27 03:20 -0800
Re: how to get arguments in a function split according to certain delimiters? "Mirko K." <mirkok.lists@googlemail.com> - 2012-02-27 13:35 +0100
Re: how to get arguments in a function split according to certain delimiters? Janis Papanagnou <janis_papanagnou@hotmail.com> - 2012-02-27 13:38 +0100
Re: how to get arguments in a function split according to certain delimiters? Paul Branon <paulbranon@googlemail.com> - 2012-02-27 05:26 -0800
Re: how to get arguments in a function split according to certain delimiters? Barry Margolin <barmar@alum.mit.edu> - 2012-02-27 11:25 -0500
Re: how to get arguments in a function split according to certain delimiters? Paul Branon <paulbranon@googlemail.com> - 2012-02-27 03:24 -0800
Re: how to get arguments in a function split according to certain delimiters? Paul Branon <paulbranon@googlemail.com> - 2012-02-27 03:27 -0800
Re: how to get arguments in a function split according to certain delimiters? "Chris F.A. Johnson" <cfajohnson@gmail.com> - 2012-02-27 15:37 -0500
Re: how to get arguments in a function split according to certain delimiters? Selva <kobu.selva@gmail.com> - 2012-02-27 20:09 -0800
Re: how to get arguments in a function split according to certain delimiters? Kaz Kylheku <kaz@kylheku.com> - 2012-02-28 05:44 +0000
Re: how to get arguments in a function split according to certain delimiters? Martin Vaeth <vaeth@mathematik.uni-wuerzburg.de> - 2012-02-28 13:31 +0000
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