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Groups > comp.soft-sys.math.mathematica > #16827

Re: complex conjugation by star

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See documentation for Conjugate.

To see traditional star notation, use TraditionalForm preference:
Traditional Form (Mathematica | Preferences... | Evaluation | Format type
of new output cells: | TraditionalForm)


Clear[conjugate]


conjugate[expr_, complexExpand_: False] :=
 Module[{expr2 = Conjugate /@ expr},
  If[complexExpand,
   Simplify[expr2,
    Element[Cases[expr, _Symbol, Infinity], Reals]],
   expr2]]


BesselJ[2, x + I y] // Conjugate


Conjugate[BesselJ[2, x + I y]]


BesselJ[2, x + I y] // conjugate


BesselJ[2, Conjugate[x] - I Conjugate[y]]


BesselJ[2, x + I y] // conjugate[#, True] &


BesselJ[2, x - I y]


A B C // Conjugate


Conjugate[A B C]


A B C // conjugate


Conjugate[A] Conjugate[B] Conjugate[C]


A + B + C // Conjugate


Conjugate[A + B + C]


A + B + C // conjugate


Conjugate[A] + Conjugate[B] + Conjugate[C]



Bob Hanlon




On Fri, Apr 18, 2014 at 1:46 AM, Brambilla Roberto Luigi (RSE) <
Roberto.Brambilla@rse-web.it> wrote:

> I have defined the following useful star complex-conjugation (common star
> exponent notation)
>
>    f_*:=f/.Complex[u_,v_]->Complex[u,-v]
>
> and it works fine. For example BesselJ[2,x+I y]* gives BesselJ[2,x-I y]
>  etc...(x,y defined/undefined).
> Also it is listable on number lists
>
> {1+i2, 5+i6}*  gives  {1-i2, 5-i6} .
>
> Unfortunately it does not work on symbols, i.e.
> A* gives A even if I have defined A as a complex number by means of
> Element[A, Complexes].
> Similarly if I define Element[{A,B,G}, Complexes]
>
> {A,B,G}* gives {A,B,G}  and (A+B+G)*  gives A+B+G.
>
> I'd like to obtain {A*,B*,G*} and A*+B*+G*    ( ! )
>
> Is it possible to fix this deficiency, unpleasant in manipulating general
> expressions where is not known
> if symbols represent real or complex variables ?
>
> Many thanks!
> Rob
>
>

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Re: complex conjugation by star Bob Hanlon <hanlonr357@gmail.com> - 2014-04-20 08:46 +0000

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