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Re: Solving Equations with 3 variables and many parameters

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From	Bob Hanlon <hanlonr357@gmail.com>
Newsgroups	comp.soft-sys.math.mathematica
Subject	Re: Solving Equations with 3 variables and many parameters
Date	Mon, 3 Mar 2014 02:35:34 +0000 (UTC)
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You need to use Equal ( == ) in the equations rather than Set ( = ).


eqns1 = {P1 == (a[1] + C*b[11] + b[12]*P2)/(2*b[11]),
   P2 == (a[2] + C*b[22] + b[21]*P1)/(2*b[22])};


sol1 = Solve[eqns1, {P1, P2}];


eqns1 /. sol1 // Simplify


{{True, True}}


eqns2 = {P1 == (a[1] + C*b[11] + b[12]*P2 + b[13]*P3)/(2*b[11]),
   P2 == (a[2] + C*b[22] + b[21]*P1 + b[23]*P3)/(2*b[22]),
   P3 == (a[3] + C*b[33] + b[31]*P1 + b[32]*P2)/(2*b[33])};


sol2 = Solve[eqns2, {P1, P2, P3}];


eqns2 /. sol2 // Simplify


{{True, True, True}}



Bob Hanlon




On Sun, Mar 2, 2014 at 1:04 AM, drascher <rascher@usfca.edu> wrote:

> Hello,
>
> I am able to get Mathematica to solve:
>
> Solve[{P1=(a[1]+C*b[11]+b[12]*P2)/(2*b[11]),
> P2=(a[2]+C*b[22]+b[21]*P1)/(2*b[22])}, {P1, P2}]
>
> but it won't solve the following (which is one more variable P3 and its
> equation):
>
> Solve[{P1=(a[1]+C*b[11]+b[12]*P2+b[13]*P3)/(2*b[11]),
> P2=(a[2]+C*b[22]+b[21]*P1+b[23]*P3)/(2*b[22]),
> P3=(a[3]+C*b[33]+b[31]*P1+b[32]*P2)/(2*b[33])}, {P1, P2, P3}]
>
> It says that it doesn't understand how to interpret the word "Solve" even
> though it does it for the first eqn.
>
> Any help is appreciated.
>
>

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Re: Solving Equations with 3 variables and many parameters Bob Hanlon <hanlonr357@gmail.com> - 2014-03-03 02:35 +0000

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