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Re: int(exp(x^n),x) and Ei

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Am 13.01.2012 22:13, schrieb Thomas D. Dean:
> Wolfram gives the result of
>
> integrate(exp(x^n),x) as
>
> integrate(exp(x^n),x) = -x*Ei[(n-1)/n](-x^n)/n
>
> http://integrals.wolfram.com/index.jsp?expr=exp(x^n)&random=false
>
> Maple just returns the original expression.
>
> How do I get the Ei form?
>
> Tom Dean

convert("-x*Ei[(n-1)/n](-x^n)/n", FromMma);

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int(exp(x^n),x) and Ei "Thomas D. Dean" <tomdean@speakeasy.org> - 2012-01-13 13:13 -0800
  Re: int(exp(x^n),x) and Ei Axel Vogt <&noreply@axelvogt.de> - 2012-01-14 09:17 +0100
  Re: int(exp(x^n),x) and Ei "G. A. Edgar" <edgar@math.ohio-state.edu.invalid> - 2012-01-14 06:59 -0700
  Re: int(exp(x^n),x) and Ei Peter Pein <petsie@dordos.net> - 2012-01-14 20:40 +0100
    Re: int(exp(x^n),x) and Ei "G. A. Edgar" <edgar@math.ohio-state.edu.invalid> - 2012-01-15 06:45 -0700

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