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Re: Ruby newbie newline question

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On 10/8/12 4:44 PM, Robert Klemme wrote:

> There's also ";" which can be used instead:
> 
> $ ruby19 -ce 'if i == 1 then print "one" elsif i == 2 then print "two" end'
> Syntax OK
> $ ruby19 -ce 'if i == 1; print "one" elsif i == 2 then print "two" end'
> Syntax OK
> $ ruby19 -ce 'if i == 1 print "one" elsif i == 2 then print "two" end'
> -e:1: syntax error, unexpected tIDENTIFIER, expecting keyword_then or
> ';' or '\n'
> if i == 1 print "one" elsif i == 2 then print "two" end
>                ^
> -e:1: syntax error, unexpected keyword_elsif, expecting $end
> if i == 1 print "one" elsif i == 2 then print "two" end
>                            ^

I see. Semicolon is a statement terminator, rather than being an
assignment terminator as in C-family languages. Useful to know.

> I'm afraid I do not have more advice here.  But this was really never a
> big issue for me IIRC.  Just code away and let the syntax check give
> your the feedback. :-)

Making conservative assumptions rather than trying to pare the code to
the minimum number of characters also sounds like good advice (i.e.,
Ruby is not Perl :).

I've been using _Learning Ruby_ from O'Reilly, which is readable but not
nearly as precise as I'd like. Thanks for the input.



-- 
Gary McGath    http://www.mcgath.com

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Ruby newbie newline question Gary McGath <garym@REMOVEmcgathREMOVE.com> - 2012-10-08 14:18 -0400
  Re: Ruby newbie newline question Robert Klemme <shortcutter@googlemail.com> - 2012-10-08 22:44 +0200
    Re: Ruby newbie newline question Gary McGath <garym@REMOVEmcgathREMOVE.com> - 2012-10-08 17:57 -0400
      Re: Ruby newbie newline question Robert Klemme <shortcutter@googlemail.com> - 2012-10-09 18:58 +0200

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