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Re: Set.new([1,2,3]) == Set.new([1,2.0,3]) returns false

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On 16.10.2014 01:54, Aarti Parikh wrote:
> I get that Set is built with a Hash and that's why this happens, but should it work like this?  Do other languages handle it differently?
>
> irb(main):019:0> Set.new([1,2,3]) == Set.new([1,2.0,3])
> => false
> irb(main):020:0> Set.new([1,2,3]) == Set.new([1,2,3])
> => true
> irb(main):021:0> 2 == 2.0
> => true
> irb(main):022:0> [2] == [2.0]
> => true

irb(main):001:0> 2 == 2.0
=> true
irb(main):002:0> 2.eql? 2.0
=> false

In other words: == is a method which conveniently matches integers and 
floats of a similar numeric value but the equivalence relation used by 
Hash takes the type into account.  It may be unusual but I think it is 
very useful the way it is.

Btw. you can also do [1,2,3].to_set. :-)

Kind regards

	robert

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Set.new([1,2,3]) == Set.new([1,2.0,3]) returns false Aarti Parikh <aarti@kitereaders.com> - 2014-10-15 16:54 -0700
  Re: Set.new([1,2,3]) == Set.new([1,2.0,3]) returns false Robert Klemme <shortcutter@googlemail.com> - 2014-10-16 08:34 +0200

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