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Re: Keyword argument default if nil

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On 04.10.2014 16:41, Jo Potts wrote:
> There's not currently a way (unless I'm mistaken) to assign a
> default  value to a keyword argument if the value passed in is nil.
>
> For example:
>
> # Proposal: Adding a '||=' causes baz to be set to "baz" if nil
> def foo(bar: 1, baz: ||= 2)
>    puts "#{bar}#{baz}"
> end
>
> foo  #=> "12"
> foo(bar: nil, baz: nil)  #=> "2"
>
> # The current way of doing this requires a duplication
> # of the declaration of the default value.
> def foo(bar: 1, baz: 2)
>    baz ||= 2
>    puts "#{bar}#{baz}"
> end

What stops you from doing this?

def foo(bar: 1, baz: nil)
    baz ||= 2
    puts "#{bar}#{baz}"
end

Kind regards

	robert

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Keyword argument default if nil Jo Potts <jopotts@gmail.com> - 2014-10-04 07:41 -0700
  Re: Keyword argument default if nil Quintus <quintus@quintilianus.eu> - 2014-10-05 10:26 +0200
  Re: Keyword argument default if nil Michael Uplawski <michael.uplawski@uplawski.eu> - 2014-10-07 13:33 +0200
  Re: Keyword argument default if nil Robert Klemme <shortcutter@googlemail.com> - 2014-10-08 12:49 +0200

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