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| From | Brian Candler <b.candler@pobox.com> |
| Newsgroups | comp.lang.ruby |
| Subject | Re: String.gsub with regex and block |
| Date | Thu, 7 Apr 2011 10:50:48 -0500 |
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Alexey Petrushin wrote in post #991484:
> Probably a stupid question, but is there a way to use :gsub replacement
> without $0 $1 $2 $3 (and without "\0\1\2\3")?
There is also $~ (Regexp.last_match); $1/$2/etc are just a facade.
> I would prefer something like:
>
> "John Smith".gsub /(.+)\s(.+)/ do |name, family|
> p [name, family]
>
> # instead of this
> p [$1, $2]
> end
"John Smith".gsub /(.+)\s(.+)/ do
name, family = $~.captures
p [name, family]
end
Not pretty, but you can wrap it up in your own method:
class String
def gsubcap(*arg)
gsub(*arg) { yield $~.captures }
end
end
"John Smith".gsubcap /(.+)\s(.+)/ do |name, family|
p [name, family]
end
--
Posted via http://www.ruby-forum.com/.
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String.gsub with regex and block Alexey Petrushin <axyd80@gmail.com> - 2011-04-07 10:25 -0500
Re: String.gsub with regex and block Reid Thompson <Reid.Thompson@ateb.com> - 2011-04-07 10:36 -0500
Re: String.gsub with regex and block Brian Candler <b.candler@pobox.com> - 2011-04-08 02:20 -0500
Re: String.gsub with regex and block Brian Candler <b.candler@pobox.com> - 2011-04-07 10:50 -0500
Re: String.gsub with regex and block 7stud -- <bbxx789_05ss@yahoo.com> - 2011-04-07 13:22 -0500
Re: String.gsub with regex and block Brian Candler <b.candler@pobox.com> - 2011-04-07 10:57 -0500
Re: String.gsub with regex and block 7stud -- <bbxx789_05ss@yahoo.com> - 2011-04-07 13:10 -0500
Re: String.gsub with regex and block Phillip Gawlowski <cmdjackryan@googlemail.com> - 2011-04-07 13:39 -0500
Re: String.gsub with regex and block jake kaiden <jakekaiden@yahoo.com> - 2011-04-07 15:57 -0500
Re: String.gsub with regex and block Sergey Avseyev <sergey.avseyev@gmail.com> - 2011-04-07 22:09 -0700
Re: String.gsub with regex and block Alexey Petrushin <axyd80@gmail.com> - 2011-04-08 07:31 -0500
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