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Groups > comp.lang.python > #22557 > unrolled thread
| Started by | Astan Chee <astan.chee@gmail.com> |
|---|---|
| First post | 2012-04-02 16:19 -0700 |
| Last post | 2012-04-03 06:12 +0100 |
| Articles | 2 — 2 participants |
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simple rsa from javascript to python Astan Chee <astan.chee@gmail.com> - 2012-04-02 16:19 -0700
Re: simple rsa from javascript to python Nobody <nobody@nowhere.com> - 2012-04-03 06:12 +0100
| From | Astan Chee <astan.chee@gmail.com> |
|---|---|
| Date | 2012-04-02 16:19 -0700 |
| Subject | simple rsa from javascript to python |
| Message-ID | <2aaac386-2223-4f70-aee5-a584dba5199a@r2g2000pbs.googlegroups.com> |
Hi, I've got a simple javascript that looks like this: var public_key_mod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var public_key_exp = "010001"; var my_text = "this is a text.,)"; var public_key = RSA.getPublicKey( public_key_mod, public_key_exp ); var encrypted_text = RSA.encrypt( my_text, public_key ); and I'm trying to convert this into python and I'm rather stuck with pycrypto as there is no example on how to make the public key with a mod and exponent (or I've probably missed it). Thanks for any help!
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| From | Nobody <nobody@nowhere.com> |
|---|---|
| Date | 2012-04-03 06:12 +0100 |
| Message-ID | <pan.2012.04.03.05.13.10.252000@nowhere.com> |
| In reply to | #22557 |
On Mon, 02 Apr 2012 16:19:05 -0700, Astan Chee wrote:
> and I'm trying to convert this into python and I'm rather stuck with
> pycrypto as there is no example on how to make the public key with a mod
> and exponent (or I've probably missed it).
from Crypto.PublicKey import RSA
mod = long("B99808B881F3D8A...", 16) # truncated for clarity
exp = long("010001", 16)
rsa = RSA.construct((mod, exp))
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