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| Started by | Daniel Kluev <dan.kluev@gmail.com> |
|---|---|
| First post | 2011-04-29 15:19 +1100 |
| Last post | 2011-04-29 15:19 +1100 |
| Articles | 1 — 1 participant |
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Re: use of index (beginner's question) Daniel Kluev <dan.kluev@gmail.com> - 2011-04-29 15:19 +1100
| From | Daniel Kluev <dan.kluev@gmail.com> |
|---|---|
| Date | 2011-04-29 15:19 +1100 |
| Subject | Re: use of index (beginner's question) |
| Message-ID | <mailman.982.1304050771.9059.python-list@python.org> |
On Thu, Apr 28, 2011 at 11:42 AM, Rusty Scalf <iai-gis@sonic.net> wrote:
> list1 = ['pig', 'horse', 'moose']
> list2 = ['62327', '49123', '79115']
> n = 2
> s2 = "list" + `n`
> a = s2[list1.index('horse')]
> print a
>
> -does not work
While advices above are indeed right way to go in your case, there is
a way to get variable by its name.
>>> list2 = ['62327', '49123', '79115']
>>> n = 2
>>> s2 = "list{0}".format(n)
>>> print s2
list2
>>> print locals()[s2]
['62327', '49123', '79115']
>>> print locals()[s2][0]
62327
But generally if you need to do that, you would be better with
re-design of your data/architecture.
--
With best regards,
Daniel Kluev
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