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Increase value in hash table

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  Increase value in hash table moonhkt <moonhkt@gmail.com> - 2013-01-22 23:26 -0800
    Re: Increase value in hash table Chris Rebert <clp2@rebertia.com> - 2013-01-22 23:34 -0800
      Re: Increase value in hash table moonhkt <moonhkt@gmail.com> - 2013-01-23 01:23 -0800
    Re: Increase value in hash table Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-01-23 10:12 +0000
      Re: Increase value in hash table Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-01-23 10:47 +0000
        Multiple postings [was Re: Increase value in hash table] Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-01-23 21:54 +1100
          Re: Multiple postings [was Re: Increase value in hash table] rusi <rustompmody@gmail.com> - 2013-01-23 06:00 -0800
      Re: Increase value in hash table Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-01-23 10:46 +0000
      Re: Increase value in hash table Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-01-23 10:46 +0000
      Re: Increase value in hash table Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-01-23 10:47 +0000
    Re: Increase value in hash table moonhk <moonhkt@gmail.com> - 2013-01-23 23:33 +0800
      Re: Increase value in hash table moonhkt <moonhkt@gmail.com> - 2013-01-23 07:39 -0800
        Re: Increase value in hash table Dave Angel <d@davea.name> - 2013-01-23 17:35 -0500
    Re: Increase value in hash table Vito De Tullio <vito.detullio@gmail.com> - 2013-01-24 19:30 +0100

#37422 — Increase value in hash table

Hi Al

I have Data file have below

Data file
V1
V2
V3
V4
V4
V3

How to using count number of data ?

Output
V1 = 1
V2 = 1
V3 =2
V4 = 2



# Global Veriable
printque = {}
in def have below

printque[val] =  printque[val] + 1

I have below error
  File "xprintlogchk.py", line 78, in chklog
    printque[val] =  printque[val] + 1
KeyError: 'nan'

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#37423

[Multipart message — attachments visible in raw view] — view raw

On Jan 22, 2013 11:31 PM, "moonhkt" <moonhkt@gmail.com> wrote:
>
> Hi Al
>
> I have Data file have below
>
> Data file
> V1
> V2
> V3
> V4
> V4
> V3
>
> How to using count number of data ?
>
> Output
> V1 = 1
> V2 = 1
> V3 =2
> V4 = 2

Construct a frequency table using collections.Counter:

http://docs.python.org/2.7/library/collections.html#collections.Counter

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#37432

On Jan 23, 3:34 pm, Chris Rebert <c...@rebertia.com> wrote:
> On Jan 22, 2013 11:31 PM, "moonhkt" <moon...@gmail.com> wrote:
>
>
>
>
>
>
>
>
>
>
>
> > Hi Al
>
> > I have Data file have below
>
> > Data file
> > V1
> > V2
> > V3
> > V4
> > V4
> > V3
>
> > How to using count number of data ?
>
> > Output
> > V1 = 1
> > V2 = 1
> > V3 =2
> > V4 = 2
>
> Construct a frequency table using collections.Counter:
>
> http://docs.python.org/2.7/library/collections.html#collections.Counter

What is problem for below ?
#!/usr/bin/env python
# Python hash {}
# Python Lists  []

global age
karry = "ER"
k1 = "EU"
age = {}
age[karry] = 3
age[k1] = 5

def ABC():
   global age
   global karry
   i = 0
   a = "A B"
   karry = a.split()
   age[karry[0]] += 1


ABC()
for key in age:
   print key,  age[key]



Result
ex_array.py
Traceback (most recent call last):
  File "ex_array.py", line 21, in <module>
    ABC()
  File "ex_array.py", line 18, in ABC
    age[karry[0]] += 1
KeyError: 'A'

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#37440

On 23 January 2013 07:26, moonhkt <moonhkt@gmail.com> wrote:
> Hi Al
>
> I have Data file have below
>
> Data file
> V1
> V2
> V3
> V4
> V4
> V3
>
> How to using count number of data ?
>
> Output
> V1 = 1
> V2 = 1
> V3 =2
> V4 = 2
>
>
>
> # Global Veriable
> printque = {}
> in def have below
>
> printque[val] =  printque[val] + 1
>
> I have below error
>   File "xprintlogchk.py", line 78, in chklog
>     printque[val] =  printque[val] + 1
> KeyError: 'nan'

You can't retrieve the value of printque[val] if you haven't yet added
an entry with the key val to the dict. Try this:

if val not in printque:
    printque[val] = 1
else:
    printque[val] = printque[val] + 1


Oscar

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#37443

On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:

> You can't retrieve the value of printque[val] if you haven't yet added
> an entry with the key val to the dict. Try this:
> 
> if val not in printque:
>     printque[val] = 1
> else:
>     printque[val] = printque[val] + 1

Another way of writing that is:

printque[val] = printque.get(val, 0) + 1



-- 
Steven

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#37449 — Multiple postings [was Re: Increase value in hash table]

Steven D'Aprano wrote:
[snip content]

Arrgggh, it's happened again. Sorry for the multiple posts folks, I *swear*
I only sent it once.

Trying this time with a different news client.


-- 
Steven

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#37466 — Re: Multiple postings [was Re: Increase value in hash table]

On Jan 23, 3:54 pm, Steven D'Aprano <steve
+comp.lang.pyt...@pearwood.info> wrote:
> Steven D'Aprano wrote:
>

> I *swear* I only sent it once.

Now Now Steven! Good boys dont swear.

> Arrgggh, it's happened again. Sorry for the multiple posts folks...
> Trying this time with a different news client.

Its a law of the universe called karma.
Thou shalt double triple quadruple post for each GG user thou tickest
off.
And the choice for instant liberation is always there:

Use GG!!

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#37446

On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:

> You can't retrieve the value of printque[val] if you haven't yet added
> an entry with the key val to the dict. Try this:
> 
> if val not in printque:
>     printque[val] = 1
> else:
>     printque[val] = printque[val] + 1

Another way of writing that is:

printque[val] = printque.get(val, 0) + 1



-- 
Steven

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#37447

On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:

> You can't retrieve the value of printque[val] if you haven't yet added
> an entry with the key val to the dict. Try this:
> 
> if val not in printque:
>     printque[val] = 1
> else:
>     printque[val] = printque[val] + 1

Another way of writing that is:

printque[val] = printque.get(val, 0) + 1



-- 
Steven

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#37448

On Wed, 23 Jan 2013 10:12:25 +0000, Oscar Benjamin wrote:

> You can't retrieve the value of printque[val] if you haven't yet added
> an entry with the key val to the dict. Try this:
> 
> if val not in printque:
>     printque[val] = 1
> else:
>     printque[val] = printque[val] + 1

Another way of writing that is:

printque[val] = printque.get(val, 0) + 1



-- 
Steven

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#37482

Works.

     prndev = line.split()
         # print line
         for key in prndev :
             if key in 'lpr':
                val = prndev[5].replace("-P","")
                if val not in printque:
                   printque[val] = 1
                else:
                   printque[val] = printque[val] + 1
             if key in "/dev/null":
                 val='null'
                 if val not in printque:
                    printque[val] = 1
                 else:
                    printque[val] = printque[val] + 1


On Wed, Jan 23, 2013 at 6:12 PM, Oscar Benjamin
<oscar.j.benjamin@gmail.com> wrote:
> On 23 January 2013 07:26, moonhkt <moonhkt@gmail.com> wrote:
>> Hi Al
>>
>> I have Data file have below
>>
>> Data file
>> V1
>> V2
>> V3
>> V4
>> V4
>> V3
>>
>> How to using count number of data ?
>>
>> Output
>> V1 = 1
>> V2 = 1
>> V3 =2
>> V4 = 2
>>
>>
>>
>> # Global Veriable
>> printque = {}
>> in def have below
>>
>> printque[val] =  printque[val] + 1
>>
>> I have below error
>>   File "xprintlogchk.py", line 78, in chklog
>>     printque[val] =  printque[val] + 1
>> KeyError: 'nan'
>
> You can't retrieve the value of printque[val] if you haven't yet added
> an entry with the key val to the dict. Try this:
>
> if val not in printque:
>     printque[val] = 1
> else:
>     printque[val] = printque[val] + 1
>
>
> Oscar



-- 
moonhkt
GMT+8

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#37484

On Jan 23, 11:33 pm, moonhk <moon...@gmail.com> wrote:
> Works.
>
>      prndev = line.split()
>          # print line
>          for key in prndev :
>              if key in 'lpr':
>                 val = prndev[5].replace("-P","")
>                 if val not in printque:
>                    printque[val] = 1
>                 else:
>                    printque[val] = printque[val] + 1
>              if key in "/dev/null":
>                  val='null'
>                  if val not in printque:
>                     printque[val] = 1
>                  else:
>                     printque[val] = printque[val] + 1
>
> On Wed, Jan 23, 2013 at 6:12 PM, Oscar Benjamin
>
>
>
>
>
>
>
>
>
> <oscar.j.benja...@gmail.com> wrote:
> > On 23 January 2013 07:26, moonhkt <moon...@gmail.com> wrote:
> >> Hi Al
>
> >> I have Data file have below
>
> >> Data file
> >> V1
> >> V2
> >> V3
> >> V4
> >> V4
> >> V3
>
> >> How to using count number of data ?
>
> >> Output
> >> V1 = 1
> >> V2 = 1
> >> V3 =2
> >> V4 = 2
>
> >> # Global Veriable
> >> printque = {}
> >> in def have below
>
> >> printque[val] =  printque[val] + 1
>
> >> I have below error
> >>   File "xprintlogchk.py", line 78, in chklog
> >>     printque[val] =  printque[val] + 1
> >> KeyError: 'nan'
>
> > You can't retrieve the value of printque[val] if you haven't yet added
> > an entry with the key val to the dict. Try this:
>
> > if val not in printque:
> >     printque[val] = 1
> > else:
> >     printque[val] = printque[val] + 1
>
> > Oscar
>
> --
> moonhkt
> GMT+8

Tried below works
  a = "A B"
   karry = a.split()
   age[karry[0]] = age.get(karry[0], 100) + 1
   age[karry[1]] = age.get(karry[1], 0) + 1
   age[karry[1]] = age.get(karry[1], 0) + 1


Result
A 101
B 2

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#37511

On 01/23/2013 10:39 AM, moonhkt wrote:
> On Jan 23, 11:33 pm, moonhk <moon...@gmail.com> wrote:
>> Works.

For some definition of 'works"


>>
>>       prndev = line.split()
>>           # print line
>>           for key in prndev :
>>               if key in 'lpr':

This test will fire if key is the letter "l", or the letter "p", or the 
letter "r".  Probably not what you want.  Suggest you change it to
          if key == "lpr":

>>                  val = prndev[5].replace("-P","")
>>                  if val not in printque:
>>                     printque[val] = 1
>>                  else:
>>                     printque[val] = printque[val] + 1
>>               if key in "/dev/null":

ditto here

>>                   val='null'
>>                   if val not in printque:
>>                      printque[val] = 1
>>                   else:
>>                      printque[val] = printque[val] + 1
>>

Of course, I don't know what prndev actually looks like, so I could be 
wrong as well.  But I doubt it "works" as written.

-- 
DaveA

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#37618

moonhkt wrote:

> Data file
> V1
> V2
> V3
> V4
> V4
> V3
> 
> How to using count number of data ?
> 
> Output
> V1 = 1
> V2 = 1
> V3 =2
> V4 = 2

import collections

with open(data_file) as f:
        print(collections.Counter(f.readlines()))


it's a start

-- 
ZeD

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