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Re: Windows subprocess.call problem

Started byTerry Reedy <tjreedy@udel.edu>
First post2013-01-21 18:38 -0500
Last post2013-01-21 18:38 -0500
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  Re: Windows subprocess.call problem Terry Reedy <tjreedy@udel.edu> - 2013-01-21 18:38 -0500

#37234 — Re: Windows subprocess.call problem

FromTerry Reedy <tjreedy@udel.edu>
Date2013-01-21 18:38 -0500
SubjectRe: Windows subprocess.call problem
Message-ID<mailman.769.1358811545.2939.python-list@python.org>
On 1/21/2013 6:22 PM, Tom Borkin wrote:
> nobody@nowhere.com <mailto:nobody@nowhere.com> had an excellent
> suggestion that worked right off the bat and achieved exactly what I was
> after. Thanks all!

And what was it?

>
> On Mon, Jan 21, 2013 at 9:04 AM, Dave Angel <d@davea.name
> <mailto:d@davea.name>> wrote:
>
>     On 01/21/2013 06:25 AM, Tom Borkin wrote:
>
>         Hi;
>         I have this code:
>         <snip>
>
>         for song in my_songs:
>             subprocess.call(['notepad.exe'__, '%s.txt' % song])
>             print song
>
>         It opens the first song and hangs on subsequent songs. It
>         doesn't open the
>         next song or execute the print until I have closed the first
>         one. I want it
>         to open all in the list, one after another, so I have all those
>         songs
>         available. Please advise.
>
>
>     Why not just pass all the filenames as parameters in one invocation
>     of notepad?  Assuming Notepad is written reasonably, that'll give it
>     all to you in one window, instead of opening many separate ones.



-- 
Terry Jan Reedy

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