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| Started by | Tom Borkin <borkintom@gmail.com> |
|---|---|
| First post | 2013-01-21 19:22 -0400 |
| Last post | 2013-01-21 19:22 -0400 |
| Articles | 1 — 1 participant |
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Re: Windows subprocess.call problem Tom Borkin <borkintom@gmail.com> - 2013-01-21 19:22 -0400
| From | Tom Borkin <borkintom@gmail.com> |
|---|---|
| Date | 2013-01-21 19:22 -0400 |
| Subject | Re: Windows subprocess.call problem |
| Message-ID | <mailman.768.1358810538.2939.python-list@python.org> |
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nobody@nowhere.com had an excellent suggestion that worked right off the bat and achieved exactly what I was after. Thanks all! Tom On Mon, Jan 21, 2013 at 9:04 AM, Dave Angel <d@davea.name> wrote: > On 01/21/2013 06:25 AM, Tom Borkin wrote: > >> Hi; >> I have this code: >> <snip> >> >> for song in my_songs: >> subprocess.call(['notepad.exe'**, '%s.txt' % song]) >> print song >> >> It opens the first song and hangs on subsequent songs. It doesn't open the >> next song or execute the print until I have closed the first one. I want >> it >> to open all in the list, one after another, so I have all those songs >> available. Please advise. >> > > Why not just pass all the filenames as parameters in one invocation of > notepad? Assuming Notepad is written reasonably, that'll give it all to > you in one window, instead of opening many separate ones. > > > -- > DaveA > -- > http://mail.python.org/**mailman/listinfo/python-list<http://mail.python.org/mailman/listinfo/python-list> >
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