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Iterate through a list and try log in to a website with urllib and re

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  Iterate through a list and try log in to a website with urllib and re Marcus <marcuscvj@gmail.com> - 2014-03-03 04:32 -0800
    Re: Iterate through a list and try log in to a website with urllib and re Marcus <marcuscvj@gmail.com> - 2014-03-03 04:35 -0800
      Re: Iterate through a list and try log in to a website with urllib and re Chris Angelico <rosuav@gmail.com> - 2014-03-03 23:44 +1100
      Re: Iterate through a list and try log in to a website with urllib and re Chris Angelico <rosuav@gmail.com> - 2014-03-03 23:45 +1100
        Re: Iterate through a list and try log in to a website with urllib and re Marcus <marcuscvj@gmail.com> - 2014-03-03 04:51 -0800
          Re: Iterate through a list and try log in to a website with urllib and re Chris Angelico <rosuav@gmail.com> - 2014-03-04 00:00 +1100
            Re: Iterate through a list and try log in to a website with urllib and re Marcus <marcuscvj@gmail.com> - 2014-03-03 05:05 -0800
      Re: Iterate through a list and try log in to a website with urllib and re Chris Angelico <rosuav@gmail.com> - 2014-03-03 23:44 +1100
    Re: Iterate through a list and try log in to a website with urllib and re Roy Smith <roy@panix.com> - 2014-03-03 08:47 -0500

#67530 — Iterate through a list and try log in to a website with urllib and re

Hello,

I'm trying to use urllib and urllib2 to open an url + login_data in a for loop. How can I display when successfully logged in and how to show when the login is denied? 

I've tried use this:

html_content = urllib2.urlopen(url).read()
re.findall('ERROR: The password you entered for the username USER is incorrect.', html_content)

1. I want to try an if statement in a for loop
2. Iterate through a list and when the first password in the list is denied. It shall continue with the next password in the list and try that one.
3. When it's successfully logged in the program will stop the loop and print out the password that matches.

I'm stuck and need some help creating this.

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#67531

This is the code right now: http://pastebin.com/pE1YZX2K

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#67532

On Mon, Mar 3, 2014 at 11:44 PM, Chris Angelico <rosuav@gmail.com> wrote:
> So basically, you're doing a dictionary attack. May I ask why you're
> doing this, exactly?

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#67533

On Mon, Mar 3, 2014 at 11:44 PM, Chris Angelico <rosuav@gmail.com> wrote:
> So basically, you're doing a dictionary attack. May I ask why you're
> doing this, exactly?

oops, misclicked.

I note that the user name 'alex' does not appear to match your name.
I'm going to want a good reason for this code to be written, else
you're on your own - I don't intend to help you steal someone else's
password.

ChrisA

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#67534

Yes, it's only for my own use on my local WordPress installation. Only educational use. 

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#67536

On Mon, Mar 3, 2014 at 11:51 PM, Marcus <marcuscvj@gmail.com> wrote:
> Yes, it's only for my own use on my local WordPress installation. Only educational use.

What are you trying to learn, exactly? How to break into a WP site?

Still dubious.

ChrisA

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#67537

It's not that hard to find a program that does this already. But I'm trying to learn how to use these modules to create this. I've started it and now i want to complete it so I can create another program and learn more about other stuff, maybe a Twitter script or something. How do I learn when not practice? 

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#67535

On Mon, Mar 3, 2014 at 11:35 PM, Marcus <marcuscvj@gmail.com> wrote:
> This is the code right now: http://pastebin.com/pE1YZX2K

That looks short enough to include in-line, no need to point us to an
external site :)

So basically, you're doing a dictionary attack. May I ask why you're
doing this, exactly?

ChrisA

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#67542

In article <fc7c1c7d-7811-4e58-a999-1f2e9b297cd3@googlegroups.com>,
 Marcus <marcuscvj@gmail.com> wrote:
 
> I'm trying to use urllib and urllib2 to open an url + login_data in a for 
> loop.

Step 1: Ignore all that crap and get http://www.python-requests.org/

> How can I display when successfully logged in and how to show when the 
> login is denied? 
> 
> I've tried use this:
> 
> html_content = urllib2.urlopen(url).read()
> re.findall('ERROR: The password you entered for the username USER is 
> incorrect.', html_content)

In the ideal case, whatever you're talking to will return a success or 
failure indication in the HTTP status code.

Lacking that, it will at least return something intended to be parsed 
(like JSON).

Lacking that (and, unfortunately, common), you're reduced to 
screen-scraping.  But, if you've got to do that, at least use a tool 
like lxml or BeautifulSoup to parse the HTML.

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