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Problem with print and output to screen

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  Problem with print and output to screen Mike <miguelcoam@gmail.com> - 2012-12-11 14:31 -0800
    Re: Problem with print and output to screen Dave Angel <d@davea.name> - 2012-12-11 17:48 -0500
    Re: Problem with print and output to screen Joel Goldstick <joel.goldstick@gmail.com> - 2012-12-11 17:53 -0500
    Re: Problem with print and output to screen Dave Angel <d@davea.name> - 2012-12-11 18:00 -0500
    Re: Problem with print and output to screen Joel Goldstick <joel.goldstick@gmail.com> - 2012-12-11 18:07 -0500
      Re: Problem with print and output to screen Mike <miguelcoam@gmail.com> - 2012-12-11 16:44 -0800
      Re: Problem with print and output to screen Mike <miguelcoam@gmail.com> - 2012-12-11 16:44 -0800

#34655 — Problem with print and output to screen

Hello, I am learning python and i have the next problem and i not understand how fix.
The script is very simple, shows in the terminal the command but, the row is divided in two:
Example:
 

/opt/zimbra/bin/zmprov ga user@example.com
|egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)" 
/opt/zimbra/bin/zmprov ga user2@example.com
|egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)"

And the correct is: 
/opt/zimbra/bin/zmprov ga user@example.com |egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)"


The script is:

#!/usr/bin/python
import os

for user in open ("email"):
        print '/opt/zimbra/bin/zmprov ga ' + user + '|egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)" '



Thanks

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#34660

On 12/11/2012 05:31 PM, Mike wrote:
> Hello, I am learning python and i have the next problem and i not understand how fix.
> The script is very simple, shows in the terminal the command but, the row is divided in two:
> Example:
>  
>
> /opt/zimbra/bin/zmprov ga user@example.com
> |egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)" 
> /opt/zimbra/bin/zmprov ga user2@example.com
> |egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)"
>
> And the correct is: 
> /opt/zimbra/bin/zmprov ga user@example.com |egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)"
>
>
> The script is:
>
> #!/usr/bin/python
> import os
>
> for user in open ("email"):
>         print '/opt/zimbra/bin/zmprov ga ' + user + '|egrep "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)" '
>
>
>

I'll assume that 'email' is a file in the current working directory.  So
when  you open it and iterate through it, each line will be stored in
'user', including its trailing newline.

When you print 'user', you're seeing the newline.

To see for yourself, you could/should have used (just before your print
statement)

           print repr(user)

which will show such things as escape sequences.

Anyway, the easiest way to fix it would be to use rstrip() on the line.

for user in open("email"):
    user = user.rstrip()
    print '/opt/...

That's assuming there's no trailing whitespace that you DO want to preserve.



-- 

DaveA

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#34661

[Multipart message — attachments visible in raw view] — view raw

When you read the file line by line the end of line character is included
in the result

try user[:-1] instead to strip the return from your printed text


On Tue, Dec 11, 2012 at 5:31 PM, Mike <miguelcoam@gmail.com> wrote:

> Hello, I am learning python and i have the next problem and i not
> understand how fix.
> The script is very simple, shows in the terminal the command but, the row
> is divided in two:
> Example:
>
>
> /opt/zimbra/bin/zmprov ga user@example.com
> |egrep
> "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)"
> /opt/zimbra/bin/zmprov ga user2@example.com
> |egrep
> "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)"
>
> And the correct is:
> /opt/zimbra/bin/zmprov ga user@example.com |egrep
> "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)"
>
>
> The script is:
>
> #!/usr/bin/python
> import os
>
> for user in open ("email"):
>         print '/opt/zimbra/bin/zmprov ga ' + user + '|egrep
> "(zimbraPrefMailForwardingAddress:|zimbraPrefMailForwardingAddress:)" '
>
>
>
> Thanks
> --
> http://mail.python.org/mailman/listinfo/python-list
>



-- 
Joel Goldstick

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#34662

On 12/11/2012 05:53 PM, Joel Goldstick wrote:
> When you read the file line by line the end of line character is included
> in the result
>
> try user[:-1] instead to strip the return from your printed text
>

The catch to that is the last line in the file might not have a
newline.  In that case, we'd be ignoring the last character of the line.

The .rstrip() method is easy, and for most purposes equivalent.  Few
text files have trailing whitespace, but many are missing the final
linefeed.



-- 

DaveA

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#34663

[Multipart message — attachments visible in raw view] — view raw

On Tue, Dec 11, 2012 at 6:00 PM, Dave Angel <d@davea.name> wrote:

> On 12/11/2012 05:53 PM, Joel Goldstick wrote:
> > When you read the file line by line the end of line character is included
> > in the result
> >
> > try user[:-1] instead to strip the return from your printed text
> >
>
> The catch to that is the last line in the file might not have a
> newline.  In that case, we'd be ignoring the last character of the line.
>
> The .rstrip() method is easy, and for most purposes equivalent.  Few
> text files have trailing whitespace, but many are missing the final
> linefeed.
>
> Point taken.  Brain freeze.  I forgot about .rstrip.  That is the way to go
>
> --
>
> DaveA
>
>


-- 
Joel Goldstick

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#34667

El martes, 11 de diciembre de 2012 20:07:09 UTC-3, Joel Goldstick  escribió:
> On Tue, Dec 11, 2012 at 6:00 PM, Dave Angel <d...@davea.name> wrote:
> 
> 
> On 12/11/2012 05:53 PM, Joel Goldstick wrote:
> 
> > When you read the file line by line the end of line character is included
> 
> > in the result
> 
> >
> 
> > try user[:-1] instead to strip the return from your printed text
> 
> >
> 
> 
> 
> The catch to that is the last line in the file might not have a
> 
> newline.  In that case, we'd be ignoring the last character of the line.
> 
> 
> 
> The .rstrip() method is easy, and for most purposes equivalent.  Few
> 
> text files have trailing whitespace, but many are missing the final
> 
> linefeed.
> 
> 
> 
> Point taken.  Brain freeze.  I forgot about .rstrip.  That is the way to go
> 
> 
> 
> --
> 
> 
> 
> DaveA
> 
> 
> 
> 
> 
> 
> -- 
> Joel Goldstick

Thank you very much, i used  "user.rstrip" and the output is correct . 

Best Regards!

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#34669

El martes, 11 de diciembre de 2012 20:07:09 UTC-3, Joel Goldstick  escribió:
> On Tue, Dec 11, 2012 at 6:00 PM, Dave Angel <d...@davea.name> wrote:
> 
> 
> On 12/11/2012 05:53 PM, Joel Goldstick wrote:
> 
> > When you read the file line by line the end of line character is included
> 
> > in the result
> 
> >
> 
> > try user[:-1] instead to strip the return from your printed text
> 
> >
> 
> 
> 
> The catch to that is the last line in the file might not have a
> 
> newline.  In that case, we'd be ignoring the last character of the line.
> 
> 
> 
> The .rstrip() method is easy, and for most purposes equivalent.  Few
> 
> text files have trailing whitespace, but many are missing the final
> 
> linefeed.
> 
> 
> 
> Point taken.  Brain freeze.  I forgot about .rstrip.  That is the way to go
> 
> 
> 
> --
> 
> 
> 
> DaveA
> 
> 
> 
> 
> 
> 
> -- 
> Joel Goldstick

Thank you very much, i used  "user.rstrip" and the output is correct . 

Best Regards!

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