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Re: suggestions, comments on an "is_subdict" test

Started byWolfgang Rohdewald <wolfgang@rohdewald.de>
First post2011-04-22 16:43 +0200
Last post2011-04-22 16:43 +0200
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  Re: suggestions, comments on an "is_subdict" test Wolfgang Rohdewald <wolfgang@rohdewald.de> - 2011-04-22 16:43 +0200

#3877 — Re: suggestions, comments on an "is_subdict" test

FromWolfgang Rohdewald <wolfgang@rohdewald.de>
Date2011-04-22 16:43 +0200
SubjectRe: suggestions, comments on an "is_subdict" test
Message-ID<mailman.752.1303483438.9059.python-list@python.org>
On Freitag 22 April 2011, Vlastimil Brom wrote:
> check whether all items of a given dictionary are
> present in a reference dictionary

I would not call this is_subdict. That name does not
clearly express that all keys need to have the same
value.

set(subdict.items()) <= set(reference.items())

should be equivalent to your code

if you only want to check for presence of all
keys in the reference dict:

set(subdict.keys()) <= set(reference.keys())

-- 
Wolfgang

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