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Groups > comp.lang.python > #66713 > unrolled thread
| Started by | Kevin Glover <kevingloveruk@gmail.com> |
|---|---|
| First post | 2014-02-19 11:39 -0800 |
| Last post | 2014-02-20 13:06 +1100 |
| Articles | 5 — 4 participants |
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Insert variable into text search string Kevin Glover <kevingloveruk@gmail.com> - 2014-02-19 11:39 -0800
Re: Insert variable into text search string MRAB <python@mrabarnett.plus.com> - 2014-02-19 19:46 +0000
Re: Insert variable into text search string Jussi Piitulainen <jpiitula@ling.helsinki.fi> - 2014-02-19 21:59 +0200
Re: Insert variable into text search string Kevin Glover <kevingloveruk@gmail.com> - 2014-02-19 12:15 -0800
Re: Insert variable into text search string Chris Angelico <rosuav@gmail.com> - 2014-02-20 13:06 +1100
| From | Kevin Glover <kevingloveruk@gmail.com> |
|---|---|
| Date | 2014-02-19 11:39 -0800 |
| Subject | Insert variable into text search string |
| Message-ID | <7a20fe74-e689-4261-b608-73d0f49736f3@googlegroups.com> |
These two lines are from a program that carries out a phrase search of Wikipedia and returns the total number of times that the specific phrase occurs. It is essential that the search contains an apostrophe:
results = w.search("\"of the cat's\"", type=ALL, start=1, count=1)
print results.total
I want to replace the word "cat" with a variable, e.g.
q = "cat"
so that I can generate the same search format for a list of different words. How do I format the search string to include the variable, please? I am using Python 2.7.
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| From | MRAB <python@mrabarnett.plus.com> |
|---|---|
| Date | 2014-02-19 19:46 +0000 |
| Message-ID | <mailman.7162.1392839218.18130.python-list@python.org> |
| In reply to | #66713 |
On 2014-02-19 19:39, Kevin Glover wrote:
> These two lines are from a program that carries out a phrase search of Wikipedia and returns the total number of times that the specific phrase occurs. It is essential that the search contains an apostrophe:
>
> results = w.search("\"of the cat's\"", type=ALL, start=1, count=1)
> print results.total
>
> I want to replace the word "cat" with a variable, e.g.
>
> q = "cat"
>
> so that I can generate the same search format for a list of different words. How do I format the search string to include the variable, please? I am using Python 2.7.
>
Try string concatenation:
results = w.search("\"of the " + q + "'s\"", type=ALL, start=1,
count=1)
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| From | Jussi Piitulainen <jpiitula@ling.helsinki.fi> |
|---|---|
| Date | 2014-02-19 21:59 +0200 |
| Message-ID | <qotmwhmkh5g.fsf@ruuvi.it.helsinki.fi> |
| In reply to | #66713 |
Kevin Glover writes:
> These two lines are from a program that carries out a phrase search
> of Wikipedia and returns the total number of times that the specific
> phrase occurs. It is essential that the search contains an
> apostrophe:
>
> results = w.search("\"of the cat's\"", type=ALL, start=1, count=1)
> print results.total
>
> I want to replace the word "cat" with a variable, e.g.
>
> q = "cat"
>
> so that I can generate the same search format for a list of
> different words. How do I format the search string to include the
> variable, please? I am using Python 2.7.
Format is the right word: look up the .format method of strings.
>>> '''"of the {q}'s"'''.format(q='kangaroo')
'"of the kangaroo\'s"'
That's with Python 2.7.3. An older mechanism uses the percent sign for
place holders and as an operator.
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| From | Kevin Glover <kevingloveruk@gmail.com> |
|---|---|
| Date | 2014-02-19 12:15 -0800 |
| Message-ID | <6e8fa7a0-f943-4802-aedd-4672ad18c352@googlegroups.com> |
| In reply to | #66713 |
Thank you both so much. I had tried % but not successfully.
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| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2014-02-20 13:06 +1100 |
| Message-ID | <mailman.7170.1392861986.18130.python-list@python.org> |
| In reply to | #66716 |
On Thu, Feb 20, 2014 at 7:15 AM, Kevin Glover <kevingloveruk@gmail.com> wrote:
> Thank you both so much. I had tried % but not successfully.
To do it with %, just do this:
whatever = "cat"
results = w.search("\"of the %s's\""%whatever, type=ALL, start=1, count=1)
Use either that or .format(), whichever you like - both are fully
supported, and they have different strengths.
ChrisA
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