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passing an option to the python interpreter

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  passing an option to the python interpreter Jabba Laci <jabba.laci@gmail.com> - 2014-02-15 23:32 +0100
    Re: passing an option to the python interpreter Marko Rauhamaa <marko@pacujo.net> - 2014-02-16 00:47 +0200
      Re: passing an option to the python interpreter Anssi Saari <as@sci.fi> - 2014-03-02 21:40 +0200

#66488 — passing an option to the python interpreter

Hi,

The first line in my scripts looks like this:

#!/usr/bin/env python

I would like to use unbuffered output in a script, which can be done
with the -u option, thus I tried this:

#!/usr/bin/env python -u

But if I want to run it from the command line ($ ./unbuffered.py), I
get this error:

/usr/bin/env: python -u: No such file or directory

env is looking for "python -u" but such a command doesn't exist.

How to overcome this problem? I could write

#!/usr/bin/python -u

but I prefer to call python through env. For instance if I put this
last one in a virtualenv, that would call the system-wide interpreter
not the one in the virtualenv.

Thanks,

Laszlo

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#66490

Jabba Laci <jabba.laci@gmail.com>:

> I tried this:
>
> #!/usr/bin/env python -u

The hash-bang notation is quite rigid; it only accepts a single argument
("python") to the command ("/usr/bin/env").

I don't know if there is a simple workaround.


Marko

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#67464

Marko Rauhamaa <marko@pacujo.net> writes:

> Jabba Laci <jabba.laci@gmail.com>:
>
>> I tried this:
>>
>> #!/usr/bin/env python -u
>
> The hash-bang notation is quite rigid; it only accepts a single argument
> ("python") to the command ("/usr/bin/env").
>
> I don't know if there is a simple workaround.

Using the relevant environment variable (PYTHONUNBUFFERED) seems simple
to me.

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