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Groups > comp.lang.python > #29149 > unrolled thread

What's wrong with my arc tangens calculation?

Started byxliiv <tymoteusz.jankowski@gmail.com>
First post2012-09-14 03:49 -0700
Last post2012-09-14 23:17 +1000
Articles 7 — 4 participants

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  What's wrong with my arc tangens calculation? xliiv <tymoteusz.jankowski@gmail.com> - 2012-09-14 03:49 -0700
    Re: What's wrong with my arc tangens calculation? Chris Angelico <rosuav@gmail.com> - 2012-09-14 20:54 +1000
    Re: What's wrong with my arc tangens calculation? Laszlo Nagy <gandalf@shopzeus.com> - 2012-09-14 12:54 +0200
      Re: What's wrong with my arc tangens calculation? xliiv <tymoteusz.jankowski@gmail.com> - 2012-09-14 04:18 -0700
      Re: What's wrong with my arc tangens calculation? xliiv <tymoteusz.jankowski@gmail.com> - 2012-09-14 04:18 -0700
    Re: What's wrong with my arc tangens calculation? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-09-14 14:13 +0100
    Re: What's wrong with my arc tangens calculation? Chris Angelico <rosuav@gmail.com> - 2012-09-14 23:17 +1000

#29149 — What's wrong with my arc tangens calculation?

Fromxliiv <tymoteusz.jankowski@gmail.com>
Date2012-09-14 03:49 -0700
SubjectWhat's wrong with my arc tangens calculation?
Message-ID<ba77717e-d812-4132-b477-cc3a79c41476@googlegroups.com>
I do some math with python:

import math as m
m.degrees(m.atan(2))
>>> 63.43494882292201

but when i lookup tg in a paper table (last decade math book) i've got these values:

tg(63'10'') = 1.9768
tg(63'20'') = 1.9912
tg(63'30'') = 2.0057

For me python should return something more like 63'2x'' than 63'4x''(becasue 63'30'' is higher than 2.0)

what's wrong?

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#29150

FromChris Angelico <rosuav@gmail.com>
Date2012-09-14 20:54 +1000
Message-ID<mailman.693.1347620057.27098.python-list@python.org>
In reply to#29149
On Fri, Sep 14, 2012 at 8:49 PM, xliiv <tymoteusz.jankowski@gmail.com> wrote:
> I do some math with python:
>
> import math as m
> m.degrees(m.atan(2))
>>>> 63.43494882292201
>
> but when i lookup tg in a paper table (last decade math book) i've got these values:
>
> tg(63'10'') = 1.9768
> tg(63'20'') = 1.9912
> tg(63'30'') = 2.0057
>
> For me python should return something more like 63'2x'' than 63'4x''(becasue 63'30'' is higher than 2.0)

According to Google:
.43494882292201 degrees = 26.0969294 arcminutes

So I would say that your table and Python are in agreement. Do you
know what the notation 63'30" means?

ChrisA

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#29151

FromLaszlo Nagy <gandalf@shopzeus.com>
Date2012-09-14 12:54 +0200
Message-ID<mailman.694.1347620106.27098.python-list@python.org>
In reply to#29149
> but when i lookup tg in a paper table (last decade math book) i've got these values:
>
> tg(63'10'') = 1.9768
> tg(63'20'') = 1.9912
> tg(63'30'') = 2.0057
>
> For me python should return something more like 63'2x'' than 63'4x''(becasue 63'30'' is higher than 2.0)
>
> what's wrong?
>
63° 30" is 63.5°. So nothing is wrong. (You know, 1° = 60 arc second!)

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#29153

Fromxliiv <tymoteusz.jankowski@gmail.com>
Date2012-09-14 04:18 -0700
Message-ID<95bea1d5-ccbd-4987-9b64-6555075a3c1b@googlegroups.com>
In reply to#29151
On Friday, September 14, 2012 12:55:06 PM UTC+2, Laszlo Nagy wrote:
> > but when i lookup tg in a paper table (last decade math book) i've got these values:
> 
> >
> 
> > tg(63'10'') = 1.9768
> 
> > tg(63'20'') = 1.9912
> 
> > tg(63'30'') = 2.0057
> 
> >
> 
> > For me python should return something more like 63'2x'' than 63'4x''(becasue 63'30'' is higher than 2.0)
> 
> >
> 
> > what's wrong?
> 
> >
> 
> 63� 30" is 63.5�. So nothing is wrong. (You know, 1� = 60 arc second!)

So the wrong part is me ;)
The python's 63.43494882292201 is degrees (according to function math.degrees)
but book's value is in minutes. Clearified Thanks, all.

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#29154

Fromxliiv <tymoteusz.jankowski@gmail.com>
Date2012-09-14 04:18 -0700
Message-ID<mailman.696.1347621517.27098.python-list@python.org>
In reply to#29151
On Friday, September 14, 2012 12:55:06 PM UTC+2, Laszlo Nagy wrote:
> > but when i lookup tg in a paper table (last decade math book) i've got these values:
> 
> >
> 
> > tg(63'10'') = 1.9768
> 
> > tg(63'20'') = 1.9912
> 
> > tg(63'30'') = 2.0057
> 
> >
> 
> > For me python should return something more like 63'2x'' than 63'4x''(becasue 63'30'' is higher than 2.0)
> 
> >
> 
> > what's wrong?
> 
> >
> 
> 63� 30" is 63.5�. So nothing is wrong. (You know, 1� = 60 arc second!)

So the wrong part is me ;)
The python's 63.43494882292201 is degrees (according to function math.degrees)
but book's value is in minutes. Clearified Thanks, all.

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#29164

FromMark Lawrence <breamoreboy@yahoo.co.uk>
Date2012-09-14 14:13 +0100
Message-ID<mailman.701.1347628381.27098.python-list@python.org>
In reply to#29149
On 14/09/2012 11:54, Chris Angelico wrote:
> On Fri, Sep 14, 2012 at 8:49 PM, xliiv <tymoteusz.jankowski@gmail.com> wrote:
>> I do some math with python:
>>
>> import math as m
>> m.degrees(m.atan(2))
>>>>> 63.43494882292201
>>
>> but when i lookup tg in a paper table (last decade math book) i've got these values:
>>
>> tg(63'10'') = 1.9768
>> tg(63'20'') = 1.9912
>> tg(63'30'') = 2.0057
>>
>> For me python should return something more like 63'2x'' than 63'4x''(becasue 63'30'' is higher than 2.0)
>
> According to Google:
> .43494882292201 degrees = 26.0969294 arcminutes
>
> So I would say that your table and Python are in agreement. Do you
> know what the notation 63'30" means?
>
> ChrisA
>

Somebody or something has a length, height or width of 63 feet 30 inches? :)

-- 
Cheers.

Mark Lawrence.

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#29165

FromChris Angelico <rosuav@gmail.com>
Date2012-09-14 23:17 +1000
Message-ID<mailman.702.1347628665.27098.python-list@python.org>
In reply to#29149
On Fri, Sep 14, 2012 at 11:13 PM, Mark Lawrence <breamoreboy@yahoo.co.uk> wrote:
> Somebody or something has a length, height or width of 63 feet 30 inches? :)

Sounds like the height of a building with a barometer. The thirty
inches, of course, being the height of the barometer.

ChrisA
(big, big barometer)

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