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| Started by | srinivas devaki <mr.eightnoteight@gmail.com> |
|---|---|
| First post | 2016-01-08 18:51 +0530 |
| Last post | 2016-01-08 18:51 +0530 |
| Articles | 1 — 1 participant |
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Re: How to remove item from heap efficiently? srinivas devaki <mr.eightnoteight@gmail.com> - 2016-01-08 18:51 +0530
| From | srinivas devaki <mr.eightnoteight@gmail.com> |
|---|---|
| Date | 2016-01-08 18:51 +0530 |
| Subject | Re: How to remove item from heap efficiently? |
| Message-ID | <mailman.67.1452259339.2305.python-list@python.org> |
You can create a single heap with primary key as timestamp and secondary key as priority, i.e by creating a tuple insert the elements into the heap as (timestamp, priority) If there is any underlying meaning for creating 2 heaps. please mention. On Fri, Jan 8, 2016 at 4:22 AM, Sven R. Kunze <srkunze@mail.de> wrote: > Hi everybody, > > suppose, I need items sorted by two criteria (say timestamp and priority). > For that purpose, I use two heaps (heapq module): > > heapA # items sorted by timestamp > heapB # items sorted by priority > > Now my actual problem. When popping an item of heapA (that's the oldest > item), I need to remove the very same item from heapB, regardlessly where it > is in heapB. And vice versa. > > Is there a datastructure or a simple trick to achieve that in an efficient > matter? > > Best, > Sven > -- > https://mail.python.org/mailman/listinfo/python-list
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