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Re: regex multiple patterns in order

Started byDevin Jeanpierre <jeanpierreda@gmail.com>
First post2014-01-20 03:09 -0800
Last post2014-01-20 03:09 -0800
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  Re: regex multiple patterns in order Devin Jeanpierre <jeanpierreda@gmail.com> - 2014-01-20 03:09 -0800

#64356 — Re: regex multiple patterns in order

FromDevin Jeanpierre <jeanpierreda@gmail.com>
Date2014-01-20 03:09 -0800
SubjectRe: regex multiple patterns in order
Message-ID<mailman.5746.1390216232.18130.python-list@python.org>
On Mon, Jan 20, 2014 at 2:44 AM, km <srikrishnamohan@gmail.com> wrote:
> I am trying to find sub sequence patterns but constrained by the order in
> which they occur
> For example
>
>>>> p = re.compile('(CAA)+?(TCT)+?(TA)+?')
>>>> p.findall('CAACAACAATCTTCTTCTTCTTATATA')
> [('CAA', 'TCT', 'TA')]
>
> But I instead find only one instance of the CAA/TCT/TA in that order.
> How can I get 3 matches of CAA, followed by  four matches of TCT followed by
> 2 matches of TA ?
> Well these patterns (CAA/TCT/TA) can occur any number of  times and atleast
> once so I have to use + in the regex.

You want to include the '+' in the parens so that repetitions are
included in the match, but you still want to group CAA etc. together;
for that, you can use non-capturing groups.

I don't see how TA could ever match two, though. It'd match once
as-is, or thrice if you make the repetition greedy (get rid of the
?s).

>>> p = re.compile('((?:CAA)+?)((?:TCT)+?)((?:TA)+?)')
>>> p.findall('CAACAACAATCTTCTTCTTCTTATATA')
[('CAACAACAA', 'TCTTCTTCTTCT', 'TA')]

-- Devin

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