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Re: Building and accessing an array of dictionaries

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  Re: Building and accessing an array of dictionaries Jean-Michel Pichavant <jeanmichel@sequans.com> - 2014-01-16 10:57 +0100

#64070 — Re: Building and accessing an array of dictionaries

----- Original Message -----
> I would like to build an array of dictionaries. Most of the
> dictionary example on the net are for single dictionary.
> 
> dict = {'a':'a','b':'b','c':'c'}
> dict2 = {'a':'a','b':'b','c':'c'}
> dict3 = {'a':'a','b':'b','c':'c'}
> 
> arr = (dict,dict2,dict3)
> 
> What is the syntax to access the value of dict3->'a'?
> 
> Thank you.
> 
> --
> https://mail.python.org/mailman/listinfo/python-list
> 

Hi,

arr = (dict,dict2,dict3) 
builds a tuple.

If you want to build a (ordered) List, which is the closest type to array (arrays don't exists in python), you may write

myList = [dict, dict2, dict3]

you can access 'a' by writing 

myList[2]['a']
Additionally:
myList[0] -> 1st element
myList[-1] -> last element
myList[3:] -> list of elements of myList from the the 4th element to the last


Accessing a list element or a dictionary value is done through the same operator []. That can be confusing at the very beginning, you'll get used to it eventually.

JM


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