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Determining version of OpenSSL linked against python?

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  Determining version of OpenSSL linked against python? Adam Mercer <ramercer@gmail.com> - 2012-01-23 14:01 -0600
    Re: Determining version of OpenSSL linked against python? Anssi Saari <as@sci.fi> - 2012-01-25 23:21 +0200
      Re: Determining version of OpenSSL linked against python? Adam Mercer <ramercer@gmail.com> - 2012-01-25 15:40 -0600

#19279 — Determining version of OpenSSL linked against python?

Hi

I'm trying to write a script that determines the version of OpenSSL
that python is linked against, using python-2.7 this is easy as I can
use:

    import ssl
    ssl.OPENSSL_VERSION

but unfortunately I need to support python-2.6, from an older script I
used the following:

    import _ssl
    ssl_lib = _ssl.__file__

to get the path to the _ssl.so module and then I parsed the output of
ldd (on linux) to get the path to the OpenSSL library and then parsed
the version from the filename. In other words it's very messy.

I had a little success using this approach but I have recently
received a bug report that this doesn't seem to work on Debian
Squeeze. When I try to query the __file__ attribute of the _ssl module
I get the following error:

>>> import _ssl
>>> _ssl.__file__
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'module' object has no attribute '__file__'
>>>

Can anyone offer any suggestions as to what is going wrong with the
above code or offer an alternative way of determining the OpenSSl
version using python-2.6?

Cheers

Adam

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#19436

Adam Mercer <ramercer@gmail.com> writes:

> Can anyone offer any suggestions as to what is going wrong with the
> above code or offer an alternative way of determining the OpenSSl
> version using python-2.6?

I suppose you could use ctypes to load the library and call SSLeay()
which returns the OpenSSL version number as a C long.

Like this:

from ctypes import *
libssl = cdll.LoadLibrary("libssl.so")
openssl_version = libssl.SSLeay()
print "%.9X" % openssl_version

This gives me 0009080FF which corresponds to 0.9.8o release which is
what I have installed in Debian Squeeze.

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#19437

On Wed, Jan 25, 2012 at 15:21, Anssi Saari <as@sci.fi> wrote:

> I suppose you could use ctypes to load the library and call SSLeay()
> which returns the OpenSSL version number as a C long.
>
> Like this:
>
> from ctypes import *
> libssl = cdll.LoadLibrary("libssl.so")
> openssl_version = libssl.SSLeay()
> print "%.9X" % openssl_version
>
> This gives me 0009080FF which corresponds to 0.9.8o release which is
> what I have installed in Debian Squeeze.

Thanks, that looks useful.

Cheers

Adam

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